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RA¯is an altitude of ΔSAT. P and Q are midpoints of SA¯and TA¯. SR=9, RT=16, QT=10, and PR=7.5.

Find SA.

Short Answer

Expert verified

SA=15

Step by step solution

01

Step 1. Consider the diagram.

Here, RA¯is an altitude of ΔSAT. P and Q are midpoints of SA¯and TA¯. SR=9, RT=16, QT=10, and PR=7.5.

02

Step 2. Show the calculation.

Consider the triangle ΔSAT.

It is given that RA¯is an altitude of ΔSAT.

So, it can be said that the triangle ΔARSis a right triangle.

Now, SA¯ is the hypotenuse of the right triangle ΔARS and P is its midpoint.

So, by theorem 5-15, the midpoint P of the hypotenuse SA¯of a right triangle ΔARSis equidistant from the three vertices.

Thus,

SP=PR=7.5

Also, P is the midpoint of SA¯. So, it implies that,

SP=PA

Therefore,

SA=SP+PA=SP+SP=7.5+7.5=15

03

Step 3. State the conclusion.

Therefore, SA=15

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