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Quad. STLM is a rhombus.

If m∠1=3x+1and m∠3=7x-11find the value of x.

Short Answer

Expert verified

The value of x is 10.

Step by step solution

01

Step 1. Description of step.

Diagonals of a rhombus bisect the vertex angles.

Here, ∠LSMis divided into ∠1and∠2, that is, m∠1=m∠2.

02

Step 2. Description of step.

Here, ∠SLTis divided into ∠3and∠4, that is, m∠3=m∠4.

03

Step 3. Description of step.

Here, ∠Sand∠Lare supplementary.

Substitute m∠3for m∠4and m∠1for m∠2 to find the value of x.

m∠1+m∠2+m∠3+m∠4=180m∠1+m∠1+m∠3+m∠3=1802m∠1+2m∠3=1802m∠1+m∠3=18023x+1+7x−11=18020x−1=180x−1=9x=10

Therefore, the value of x is 10.

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