91Ó°ÊÓ

Plot the point$\left(2,50°\right)$ on grid system as 2 cm from origin at an angle of$50°$ anticlockwise.

Usea protractor and a centimetre ruler todraw the triangle as shown in the figure thenmeasure the sides of triangle.

$\begin{array}{l}x=1.28\text{cm}\\ y=1.58\text{cm}\end{array}$

Conversion of point from distance-angle system to grid system is $\left(x,y\right)$

Thus,$\left(2,50°\right)=\left(1.28,1.58\right)$

Plot the point$\left(1.5,−70°\right)$ on grid system as$1.5$cm from origin at an angle of$70°$ clockwise.

Usea protractor and a centimetre ruler todraw the triangle as shown in the figure thenmeasure the sides of triangle.

$\begin{array}{l}x=0.51\text{cm}\\ y=−1.41\text{cm}\end{array}$

Conversion of point from distance-angle system to grid system is $\left(x,y\right)$

Thus,$\left(1.5,−70°\right)=\left(0.51,−1.41\right)$

Plot the point$\left(3,90°\right)$ on grid system as 3 cm from origin at an angle of$90°$ anticlockwise.

Usea protractor and a centimetre ruler todraw the triangle as shown in the figure thenmeasure the sides of triangle.

$\begin{array}{l}x=0\text{cm}\\ y=3\text{cm}\end{array}$

Conversion of point from distance-angle system to grid system is $\left(x,y\right)$

Thus,$\left(3,90°\right)=\left(0,3\right)$

Plot the point$\left(1,120°\right)$ on grid system as 1 cm from origin at an angle of$120°$ anticlockwise.

Usea protractor and a centimetre ruler todraw the triangle as shown in the figure thenmeasure the sides of triangle.

$\begin{array}{l}x=−0.5\text{cm}\\ y=0.86\text{cm}\end{array}$

Conversion of point from distance-angle system to grid system is$\left(x,y\right)$

Thus,width="156">1,120°=−0.5,0.86