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91Ó°ÊÓ

Draw any∠AOB and its bisector role="math" localid="1646847955601" OE↔. Now draw the rays opposite to OA↔,OB↔ and OE↔. What can you conclude about the part of the diagram shown in red? Prove your conclusion.

Short Answer

Expert verified

The thing that can be concluded about the part of the diagram shown in red is that the ray OF→bisects the angle ∠CODthat implies role="math" localid="1646848105169" ∠3≅∠4.

The proof of the conclusion is:

It is being given that OE→is the bisector of ∠AOB.

Therefore, ∠1≅∠2.

From the diagram, it can be noticed thatangles∠1 and∠4are the vertically opposite angles.

Therefore, ∠1≅∠4.

From the diagram, it can be noticed that angles∠2 and∠3 are the verticallyopposite angles.

Therefore, ∠2≅∠3.

Now, it can be noticed that:

∠1=∠2∠4=∠2∵∠1≅∠4∠4=∠3∵∠2≅∠3

Therefore, ∠3≅∠4.

Therefore, it can be said that the ray OF→bisects the angle ∠COD.

Hence proved.

Step by step solution

01

Step 1. Observe the diagram.

The given diagram is:

02

Step 2. Description of step.

The thing that can be conclude about the part of the diagram shown in red is that the rayOF→ bisects the angle∠COD that implies ∠3≅∠4.

03

Step 3. Description of step.

It is being given thatOE→ is the bisector of ∠AOB.

Therefore, ∠1≅∠2.

From the diagram it can be noticed that theangles∠1 and∠4 are the vertically opposite angles.

Therefore, ∠1≅∠4.

From the diagram it can be noticed that the angles∠2 and∠3 are the verticallyopposite angles.

Therefore, ∠2≅∠3.

Now, it can be noticed that:

∠1=∠2∠4=∠2∵∠1≅∠4∠4=∠3∵∠2≅∠3

Therefore, ∠3≅∠4.

Therefore, it can be said thatthe rayOF→ bisects the angle ∠COD.

Hence proved.

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