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A line passes through points (-2, -1) and (4, 3). Where does the line intersect the x-axis? the y-axis?

Short Answer

Expert verified

The required point of intersection of line withx−²¹³æ¾±²õ â¶Ä‰â¶Ä‰i²õ â¶Ä‰(−12,0) â¶Ä‰a²Ô»å â¶Ä‰y−²¹³æ¾±²õ â¶Ä‰i²õ â¶Ä‰(0,13)

Step by step solution

01

Step-1 – Given

Given that a line passes through points(−2,−1) and(4,3) .

02

Step-2 – To determine

We have tofind the point of intersection of line withx-axis and y-axis.

03

Step-3 – Calculation 

The two-point formula using these two points(x1,y1) â¶Ä‰a²Ô»å â¶Ä‰(x2,y2) is:

y−y1=y2−y1x2−x1(x−x1)

The given points are (−2,−1)and(4,3) .

y−(−1)=3−(−1)4−(−2)(x−(−2))y+1=23(x+2)3y+3=2x+43y−2x=1

The equation of the x-axis is y = 0, we solve it with3y−2x=1 .

3y−2x=13(0)−2x=1−2x=1x=−12

Equation of the y-axis is x = 0, solving it with3y−2x=1 .

3y−2x=13y−2(0)=13y=1y=13

So, the required point of intersection of line withx−²¹³æ¾±²õ â¶Ä‰â¶Ä‰i²õ â¶Ä‰(−12,0).

 â¶Ä‰a²Ô»å â¶Ä‰y−²¹³æ¾±²õ â¶Ä‰i²õ â¶Ä‰(0,13)

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