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Find the center and the radius of the circlex2+4x+y2−8y=16.

(Hint: Express the given equation in the form

x−a2+y−b2=r2)

Short Answer

Expert verified

The center is (-2, 4) and the radius is 6.

Step by step solution

01

Step-1 – Given

The given equation is: x2+4x+y2−8y=16.

02

Step-2 – To determine

We have to find the center and radius of the given circle.

03

Step-3 – Calculation 

We first write the equation to the standard form of a circle:

x2+4x+y2−8y=16x2+4x+4+y2−8y+16=16+20addbothsides20x2+22x+22+y2−24y+42=36perfectsquaretrinomialx+22+y−42=62

The standard form of a circle is:x−a2+y−b2=r2

Where (a, b) = center and r = radius.

Then we compare the given equation to the standard form of a circle:

a=−2,b=4andr=6.

So, the center is (-2, 4) and the radius is 6.

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