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Chapter 13: Q. 19 (page 526)

Find the center and radius of each circle.

x鈭�j2+y+142=17

Short Answer

Expert verified

The center is (j, -14) and the radius is 17.

Step by step solution

01

Step-1 – Given

The given equation is x鈭�j2+y+142=17.

02

Step-2 – To determine

We have to find the center and the radius of the given circle.

03

Step-3 – Calculation 

We compare the given equationx鈭�j2+y+142=17 with the standard form of a circle:x鈭�a2+y鈭�b2=r2.

Here (a, b) is the center and r being the radius.

Comparing the two equations we get: a = j, b = -14andr =17 .

So, the center is (j, -14) and the radius is17 .

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