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Chapter 13: Q. 16 (page 533)

In Exercises 16-19 a point P on a line and the slope of the line are given. Sketch the line and find the coordinates of two other points on the line.

P(-2, 1); slope =13.

Short Answer

Expert verified

The sketch is:

The equation of linex鈭�3y=鈭�5 is and the other two points on the line are0,53and1,2 .

Step by step solution

01

Step-1 – Given

The given coordinate and slope of the point is:P鈭�2,1;slope=13 .

02

Step-2 – To determine

We have to sketch the line and find the coordinates of two other points on the line.

03

Step-3 – Calculation 

We鈥檒l use the point-slope formula.

y鈭�y1=mx鈭�x1, where m is the slope of the line.

Here,P鈭�2,1;slope=13 .

So,

y鈭�1=13x鈭�鈭�23y鈭�3=x+2x鈭�3y=鈭�5

Then we sketch the linex鈭�3y=鈭�5 .

Now we use hit and trial method to get the other two points.

Plug x = 0

x鈭�3y=鈭�50鈭�3y=鈭�5y=53

Plug x = 1

x鈭�3y=鈭�51鈭�3y=鈭�5y=2

So, the equation of line isx鈭�3y=鈭�5and the other two points on the0,53and1,2line are .

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Most popular questions from this chapter

Find the slope and length of AB.

A(-3, -2), B(7, -6)

11. Find the center and the radius of each circle.

a. (x-2)2+y2=1

b. (x+2)2+(y-8)2=16

c. x2+(y+5)2=112

d. (x+3)2+(y+7)2=14

Find the slope of the line.

In Exercises 4-9 state:

a. the coordinates of T.

b. the lengths of the legs of the right triangle.

c. the length of the segment shown.

Given points A, B, and C. Find AB, BC, and AC. Are A, B, and C collinear?

If so, which point lies between the other two?

14. A(5, -5), B(0, 5), C(2, 1)
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