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In many proofs you may find that different methods can be used. You may not know in advance which method will be better. There are two possible pairs of overlapping triangles that could be used in this proof. To compare the two methods, write a two-column proof for each plan.

Given: PR¯≅PQ¯; SR¯≅TQ¯

Prove: QS¯≅RT¯

a. plan for proof: show that ΔRQS≅ΔQRTby SAS.

b. plan for proof: show thatΔPQS≅ΔPRT by SAS.

Short Answer

Expert verified

a. The two-column proof is:

Statements

Reasons

PR¯≅PQ¯,SR¯≅TQ¯

Given

∠PRQ≅∠PQR

angles opposite to the equal sides PRand PQwill also be equal

ΔRQS≅ΔQRT

SAS postulate

b. The two-column proof is:

Statements

Reasons

PR¯≅PQ¯,SR¯≅TQ¯

Given

PR=PS+SR,PQ=PT+TQ

Segment addition postulate

PT≅PS

As, PR=PS+SR, PQ=PT+TQ,PR¯≅PQ¯and SR¯≅TQ¯

ΔPQS≅ΔPRT

SAS postulate

Step by step solution

01

Part a. Step 1. Observe the given diagram.

The given diagram is:

02

Part a. Step 2. Description of step.

It is being given that PR¯≅PQ¯and SR¯≅TQ¯.

As, PR¯≅PQ¯, therefore,the angles opposite to the equal sides will also be equal.

Therefore, ∠PRQ≅∠PQR.

In the triangles width="48" height="19" role="math">ΔRQSand ΔQRT, it can be noticed that:

SR¯≅TQ¯,∠PRQ≅∠PQRand RQ≅RQ.

Therefore, the triangles ΔRQSand ΔQRTare the congruent triangles by using SAS postulate.

Therefore,ΔRQS≅ΔQRT.

03

Part a. Step 3. Description of step.

The two-column proof is:

Statements

Reasons

PR¯≅PQ¯,SR¯≅TQ¯

Given

∠PRQ≅∠PQR

angles opposite to the equal sides PRandPQwill also be equal

ΔRQS≅ΔQRT

SAS postulate

04

Part b. Step 1. Observe the given diagram.

The given diagram is:

05

Part b. Step 2. Description of step.

It is being given that PR¯≅PQ¯and SR¯≅TQ¯.

From the given diagram it can be noticed that:

PR=PS+SRand PQ=PT+TQ

As, PR¯≅PQ¯, therefore it can be obtained that:

PR=PQPS+SR=PT+TQPS+TQ=PT+TQPS=PT

Therefore, PT≅PS.

In the triangles ΔPQSand ΔPRT, it can be noticed that:

PR¯≅PQ¯, ∠P≅∠Pand PT≅PS.

Therefore, the triangles ΔPQSand ΔPRTare the congruent triangles by using SAS postulate.

Therefore,ΔPQS≅ΔPRT.

06

Part b. Step 3. Description of step.

The two-column proof is:

Statements

Reasons

PR¯≅PQ¯,SR¯≅TQ¯

Given

PR=PS+SR,PQ=PT+TQ

Segment addition postulate

PT≅PS

As, PR=PS+SR,PQ=PT+TQ,PR¯≅PQ¯ andSR¯≅TQ¯

ΔPQS≅ΔPRT

SAS postulate

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