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For Exercises 23-27 write proofs in paragraph form. (Hint: You can use theorems from this section to write fairly short proofs for Exercises 23 and 24.)

23. Given:SR↔is the ⊥bisector ofQT¯;QR↔is the⊥bisector ofSP¯

Prove:PQ=TS

Short Answer

Expert verified

Since, QR↔is the perpendicular bisector of PS¯, so the point Qis equidistance from endpoints Pand Sthat is PQ=QS. Also, SR↔is the perpendicular bisector of QT¯, so the point Sis equidistance to endpoints Qand Tthat is QS=TS. By using reflexive property,

PQ=QSandQS=STimplies PQ=TS.

Step by step solution

01

Step 1. Show that PQ=QS.

Since,QR↔ is the perpendicular bisector of PS¯, so the point Qis equidistance from endpoints Pand S. ThusPQ=QS

02

Step 2. Show that QS=ST.

Since, SR↔is perpendicular bisector of role="math" localid="1649243006755" QT¯, so point role="math" localid="1649243017087" Sis equidistance from endpoints Qand T. ThusQS=TS

03

Step 3. Use reflexive property.

By using reflexive property, for real numbers a,band role="math" localid="1649242924111" c. if

a=bandb=cthen a=c

So PQ=QSandQS=STimplies PQ=TS

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