91Ó°ÊÓ

It is being given that$â–³EFG$is isosceles, with $m∠Gâ‰\dots 94$.

In the isosceles triangle, two angles of the triangle are congruent and the sides opposite to those congruent angles are also congruent.

As, the sum of the angles of the triangle is $180°$.

If the angle $∠G$is taken as the congruent angle, then the two angles of the triangle will be of measure $94°$and the sum of the congruent angles will be more than $180°$.

Therefore, the angle $∠G$cannot be taken as the congruent angle.

Therefore, the angle $∠G$is taken as the non-congruent angle

Therefore, the legs of the triangles localid="1649248863852" $â–³EFG$are sides localid="1649248867749" $GE$and $GF$.

As, the legs of the triangles $△EFG$ are sides $GE$ and $GF$, therefore the angles $∠E$ and $∠F$ are congruent angles.

Therefore, the measures of the angles $∠E$ and $∠F$ are equal.

As, the sum of the angles of the triangle is +, therefore, the sum of the angles $∠E$,$∠F$ and $∠G$ is $180°$ and $∠E=∠F$.

Therefore, it can be obtained that:

$$\begin{gathered} ∠E+∠F+∠G=180° \\ ∠E+∠E+94°=180° \end{gathered}$$

$$\begin{gathered} 2∠E=180°−94° \\ 2∠E=86° \\ ∠E=\frac{86°}{2} \\ ∠E=43° \end{gathered}$$

Therefore, the measure of the angle $∠E$ is $43°$.

Therefore, it can be seen thatlegs are sides $GE$ and $GF$ and $m∠E=43$.

Therefore, the complete statement is: $â–³EFG$ is isosceles, with $m∠Gâ‰\dots 94$. The legs are sides $GE$ and $GF$. $m∠Eâ‰\dots 43$.