91Ó°ÊÓ

Here, the two triangles are congruent.

As, the two triangles are congruent, $\mathrm{Δ}PAL$ is congruent to $\mathrm{Δ}RLA$.

Therefore, $\mathrm{Δ}PALâ‰\dots \mathrm{Δ}RLA$.

Here, the two triangles are congruent.

As $\mathrm{Δ}PALâ‰\dots \mathrm{Δ}RLA$, the corresponding parts of the congruent tringles are also congruent.

Therefore, $\stackrel{¯}{PA}â‰\dots \stackrel{¯}{RA}$.

Here, the two triangles are congruent.

As $\mathrm{Δ}PALâ‰\dots \mathrm{Δ}RLA$, the corresponding parts of the congruent tringles are also congruent.

Therefore, $∠1â‰\dots ∠3$.

As, alternate interior angles $∠1â‰\dots ∠3$are equal, therefore, $\stackrel{¯}{PA}$is parallel to $\stackrel{¯}{RL}$.

Here, the two triangles are congruent.

As$\mathrm{Δ}PALâ‰\dots \mathrm{Δ}RLA$, the corresponding parts of the congruent triangles are also congruent.

Therefore, $∠2â‰\dots ∠4$.

Since, alternate interior angles $∠2â‰\dots ∠4$are equal, thus, $\stackrel{¯}{PL}$will be parallel to $\stackrel{¯}{AR}$.