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91Ó°ÊÓ

Solve each equation by factoring or by using the quadratic formula. The quadratic formula is:

If ax2+bx+c=0, with a≠0, thenx=−b±b2−4ac2a.

z2=4(2z−3)

Short Answer

Expert verified

The values of z arez=6and z=2.

Step by step solution

01

- Understand the concept used 

Ifax2+bx+c=0 , with a≠0, then x=−b±b2−4ac2a. Solving using factoring can be done by splitting the middle term of equation and then making groups and equating them to zero.

02

- Substitute the values 

It is given thatz2=4(2z−3)which can also be written asz2−8z+12=0 .Using quadratic formulaz=−b±b2−4ac2a, substitute 1 for a, -8 for b and 12 for c.

Put the values in the formula and getz=−−8±−82−4×1×1221 .

03

- Simplify for z 

Simplify the expression for z.

z=−−8±−82−4×1×1221=8±64−482=8±162=8±42

Therefore, either z=8+42=122or z=8−42=42that is., eitherz=6 orz=2 .

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