91Ó°ÊÓ

The given information is about the circle where $m\stackrel{Áåœ}{AB}$ and $m\stackrel{Áåœ}{BC}$ are the arcs of the circle.

$m\stackrel{Áåœ}{AB}$ means central angle of arc $AB$and $m\stackrel{Áåœ}{BC}$means central angle of arc $BC.$ .

In the figure shown below, it is clear that $m\stackrel{Áåœ}{AB}+m\stackrel{Áåœ}{BC}$ does not equal to $m\stackrel{Áåœ}{AC}.$

$mAB$means central angle of arc $AB$and $m\stackrel{Áåœ}{BC}$means central angle of arc $BC.$.

In the figure shown below, it is clear that $m\stackrel{Áåœ}{AB}+m\stackrel{Áåœ}{BC}$does not equal to $m\stackrel{Áåœ}{AC}.$

Here,$\begin{array}{c}m\stackrel{Áåœ}{AB}=90+110\\ =200\end{array}$

$\begin{array}{l}m\stackrel{Áåœ}{BC}=110\\ m\stackrel{Áåœ}{AC}=90\end{array}$

The given information is about the circle where $m\stackrel{Áåœ}{AB}$ and $m\stackrel{Áåœ}{BC}$ are the arcs of the circle

$m\stackrel{Áåœ}{AB}$means central angle of arc $AB$and $m\stackrel{Áåœ}{BC}$means central angle of arc $BC.$ .

In the figure shown below, it is clear that $m\stackrel{Áåœ}{AB}+m\stackrel{Áåœ}{BC}$ does not equal to $m\stackrel{Áåœ}{AC}.$

$m\stackrel{Áåœ}{AB}$means central angle of arc $AB$and $m\stackrel{Áåœ}{BC}$means central angle of arc $BC.$.

In the figure shown below, it is clear that $m\stackrel{Áåœ}{AB}+m\stackrel{Áåœ}{BC}$does not equal to $m\stackrel{Áåœ}{AC}.$

Here,$\begin{array}{c}m\stackrel{Áåœ}{AB}=90+110\\ =200\end{array}$

$\begin{array}{l}m\stackrel{Áåœ}{BC}=110\\ m\stackrel{Áåœ}{AC}=90\end{array}$

According to theorem,

$m\stackrel{Áåœ}{AC}+m\stackrel{Áåœ}{BC}=m\stackrel{Áåœ}{AB}$

It does not contradict the postulate, here points are interchanged.