/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q4. Given PA¯ and PB¯ are tangent... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Given PA¯and PB¯ are tangents to ⊙o.

Use the diagram at the right to explain how the corollary on page 333

follows from Theorem9-1.

Short Answer

Expert verified

a. Tangent PA is congruent to tangent PB.

Step by step solution

01

Step 1. Given information:

The figure is given.

02

Step 2. Concept used:

We used the theorem 9-1.

03

Step 3. Applying the concept:

If the line is tangent to a circle, then the line is perpendicular to the radius drawn to the point of tangents.

Then,

OA⊥PAOB⊥PB

Then once can say that,

∠PAO=90∘∠PBO=90∘
It is required to prove two triangles are congruent.

Consider in â–µPAO and â–µPBO,

OA=OB∠PAO=∠PBOPO=OP

(Radius of a circle is equal)

(Both the angles are )

(Common side of a triangle)

So, it implies that

▵PAO≅▵PBO ( Side-Angle-Side Rule)

Since the corresponding parts of congruent triangles are congruent.

Therefore, the following holds good PA and PB.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.