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91Ó°ÊÓ

JK¯ is tangent to ⊙P and ⊙Q.

JK=?

Short Answer

Expert verified

The given quadrilateral JPQK must be a Trapezium.

Step by step solution

01

Step 1. Given information.

The figure here given is,

JK is tangent to the circle with centers P and Q.

02

Step 2. Draw the construction in figure.

The measures of the sides are,

PQ=17QK=3PD=3PJ=11

OT is required to find the measures of sides JDand JK.

Now,

PJ⊥JK And QK⊥JK

Joint PJand QKand make a line parallel to PQ that is DK.

Then, it implies that,

PQ=DK=17 ........(1)

To find DK,

03

Step 3. Concept used.

Triangle JKD is a right angle triangle so one can use Pythagoras Theorem,

The measures of sides in this right angle triangle are,

DK=17JD=11–3=8

04

Step 4. Use Pythagoras Theorem as follows.

DK²=JK²+JD²17²=JK²+8²289=JK²+64JK²=289–64=225

Take positive square to get,

JK=15

So, the required length is JK=15.

In quadrilateral PQJK, sum one pair of adjacent angle is 180°.

Therefore, it can be concluded that the opposite sides is parallel.

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