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Copy and complete the table below for the regular square pyramid.

Height, h6³§±ô²¹²Ô³Ù â¶Ä‰H±ð¾±²µ³ó³Ù, lµþ²¹²õ±ð â¶Ä‰e»å²µ±ð³¢²¹³Ù±ð°ù²¹±ô â¶Ä‰e»å²µ±ð10

Short Answer

Expert verified

Height, h6³§±ô²¹²Ô³Ù â¶Ä‰H±ð¾±²µ³ó³Ù, l217µþ²¹²õ±ð â¶Ä‰e»å²µ±ð82³¢²¹³Ù±ð°ù²¹±ô â¶Ä‰e»å²µ±ð10

Step by step solution

01

Step 1. Given information.

The height and lateral edge of a regular square pyramid are 6 and 10 unit respectively.

02

Step 2. Write the concept.

The base edge is given by:

Baseedge=2(l)2−(h)2

And the lateral edge is given by:

lateraledge=(l)2+(baseedge2)2

03

Step 3. Determine the values.

Substitute all the given values in the formula.

Lateraledge=(l)2+(baseedge2)210=(l)2+((l)2−(6)2)2[substitute]100=l2+l2−36[square]

So, the slant height is:

2l2=136[add]l2=68 [»å¾±±¹¾±»å±ð±Õl=217[simplify]

And

Baseedge=2(l)2−(h)2=2(217)2−(6)2[substitute]=268−36[square]

Then,

Baseedge=232[subtract]=82[simplify]

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