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Copy and complete the table below for the regular square pyramid.

Height, h³§±ô²¹²Ô³Ù â¶Ä‰H±ð¾±²µ³ó³Ù, l12µþ²¹²õ±ð â¶Ä‰e»å²µ±ð³¢²¹³Ù±ð°ù²¹±ô â¶Ä‰e»å²µ±ð15

Short Answer

Expert verified

Height, h37³§±ô²¹²Ô³Ù â¶Ä‰H±ð¾±²µ³ó³Ù, l12µþ²¹²õ±ð â¶Ä‰e»å²µ±ð18³¢²¹³Ù±ð°ù²¹±ô â¶Ä‰e»å²µ±ð15

Step by step solution

01

Step 1. Given information.

The slant height and lateral edge of a regular square pyramid are 12 and 15 unit respectively.

02

Step 2. Write the concept.

The base edge is given by:

Baseedge=2(l)2−(h)2

And the lateral edge is given by:

lateraledge=(l)2+(baseedge2)2

03

Step 3. Determine the values.

Substitute all the given values in the formula.

Lateraledge=(l)2+(baseedge2)215=(12)2+(baseedge2)2[substitute]225=144+(baseedge2)2[square]

So,

(baseedge2)2=81[subtract]baseedge2=9 [²õ±ç²¹³Ü°ù±ð°ù´Ç´Ç³Ù±Õbaseedge=18[multiply]

And

Baseedge=2(l)2−(h)218=2(12)2−(h)2[substitute]9=144−h2[squareanddivide]

So, the height is:

144−h2=81[square]h=37[simplify]

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