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Copy and complete the table below for the regular square pyramid.

Height, h24³§±ô²¹²Ô³Ù â¶Ä‰H±ð¾±²µ³ó³Ù, lµþ²¹²õ±ð â¶Ä‰e»å²µ±ð14³¢²¹³Ù±ð°ù²¹±ô â¶Ä‰e»å²µ±ð

Short Answer

Expert verified

Height, h24³§±ô²¹²Ô³Ù â¶Ä‰H±ð¾±²µ³ó³Ù, l25µþ²¹²õ±ð â¶Ä‰e»å²µ±ð14³¢²¹³Ù±ð°ù²¹±ô â¶Ä‰e»å²µ±ð674

Step by step solution

01

Step 1. Given information.

The height and base edge of a regular square pyramid are 24 and 14 unit respectively.

02

Step 2. Write the concept.

The base edge is given by:

Baseedge=2(l)2−(h)2

And the lateral edge is given by:

lateraledge=(l)2+(baseedge2)2

03

Step 3. Determine the values.

Substitute all the given values in the formula.

Baseedge=2(l)2−(h)214=2(l)2−(24)2[substitute]7=l2−576[squareanddivide]

So,

l2−576=49[square]l=25[simplify]

And

Lateraledge=(25)2+(7)2[substitute]=674[simplify]

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