91Ó°ÊÓ

Bases of isosceles trapezoid are 10 and 4 and legs 5 and height is 20.

The lateral area of the isosceles trapezoid prism is given by:

$\text{L.A.}=\text{Perimeter}×\text{Height}$

The total area of the isosceles trapezoid prism is given by:

$\text{T.A.}=\text{L.A.+2}(\frac{1}{2}(b_1+b_2)×l)$

The volume of isosceles trapezoid prism is given by:

$\text{V}=(\frac{1}{2}(b_1+b_2)×l)×h$

Now to draw a prism first make its base as a triangle and then sketch the length of 10 triangle from its each point,

Thus, the prism can be obtained as:

The lateral area is:

$\begin{array}{c}\text{L.A.}=\text{Perimeter}×\text{Height}\\ =(10+10+5+5)×20\\ =\left(30\right)×20\\ =600{\text{ â¶Ä‰u²Ô¾±³Ù}}^2\end{array}$

The total area is:

$\begin{array}{c}\text{T.A.}=\text{L.A.+2}(\frac{1}{2}(b_1+b_2)×l)\\ =600+2(\frac{1}{2}(10+10)×5)\\ =600+2(10×5)\\ =600+100\\ =700{\text{ â¶Ä‰u²Ô¾±³Ù}}^2\end{array}$

And the volume is:

$\begin{array}{c}\text{V}=(\frac{1}{2}(b_1+b_2)×l)×h\\ =2(\frac{1}{2}(10+10)×5)×20\\ =100×20\\ =2000{\text{ â¶Ä‰u²Ô¾±³Ù}}^3\end{array}$