91Ó°ÊÓ

Sides of isosceles triangle are 13, 13, 10 and height is 7.

The lateral area of the isosceles triangular prism is given by:

$\text{L.A.}=(2×\text{³¢±ð²Ô²µ³Ù³ó â¶Ä‰o´Ú â¶Ä‰e±ç³Ü²¹±ô â¶Ä‰s¾±»å±ð²õ}+\text{´¡²Ô´Ç³Ù³ó±ð°ù â¶Ä‰s¾±»å±ð})×\text{Height}$

The total area of the isosceles triangular prism is given by:

$\text{T.A.}=\text{L.A.+2}\left(\frac{1}{2}bh\right)$

The volume of isosceles triangular prism is given by:

$\text{V}=\frac{1}{2}bhl$

Now to draw a prism first make its base as a triangle and then sketch the length of 10 triangle from its each point,

Thus, the prism can be obtained as:

The lateral area is:

$\begin{array}{c}\text{L.A.}=(2×\text{³¢±ð²Ô²µ³Ù³ó â¶Ä‰o´Ú â¶Ä‰e±ç³Ü²¹±ô â¶Ä‰s¾±»å±ð²õ}+\text{´¡²Ô´Ç³Ù³ó±ð°ù â¶Ä‰s¾±»å±ð})×\text{Height}\\ =(2×13+10)×7\\ =36×7\\ =252{\text{ â¶Ä‰u²Ô¾±³Ù}}^2\end{array}$

The total area is:

$\begin{array}{c}\text{T.A.}=\text{L.A.+2}\left(\frac{1}{2}bh\right)\\ =252+(13×10)\\ =252+130\\ =382{\text{ â¶Ä‰u²Ô¾±³Ù}}^2\end{array}$

And the volume is:

$\begin{array}{c}\text{V}=\frac{1}{2}bhl\\ =\frac{1}{2}(13×10×7)\\ =\frac{1}{2}×910\\ =455{\text{ â¶Ä‰u²Ô¾±³Ù}}^3\end{array}$