Chapter 1: Problem 3
In any triangle \(A B C,(A B C)=a b c / 4 R\).
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 1: Problem 3
In any triangle \(A B C,(A B C)=a b c / 4 R\).
These are the key concepts you need to understand to accurately answer the question.
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Let three congruent circles with one common point meet again in three points \(A, B, C\). Then the common radius of the three given circles is equal to the circumradius of \(\triangle A B C\), and their common point is its orthocenter.
Show that, \(\uparrow\) for any triangle \(A B C\), even if \(B\) or \(C\) is an obtuse angle, \(a=b \cos C+c \cdot \cos B\). Use the Law of Sines to deduce the "addition formula" $$ \sin (B+C)=\sin B \cos C+\sin C \cos B $$
If lines \(P B\) and \(P D\), outside a parallelogram \(A B C D\), make equal angles with the sides \(B C\) and \(D C\), respectively, as in Figure \(1.9 \mathrm{D}\), then \(\angle C P B=\angle D P A\). (Of course, this is a plane figure, not three dimensionall)
\(\frac{1}{r_{a}}+\frac{1}{n_{0}}+\frac{1}{r_{c}}=\frac{1}{r}\)
The circumcircle of \(\triangle A B C\) is the nine-point circle of \(\triangle I_{a} I_{s} I_{e}\).
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