Chapter 9: Problem 12
In Exercises \(11-18,\) Ind the geometric mean of the two numbers. 9 and 16
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Chapter 9: Problem 12
In Exercises \(11-18,\) Ind the geometric mean of the two numbers. 9 and 16
These are the key concepts you need to understand to accurately answer the question.
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REASONING Explain why it is not possible to ?nd the tangent of a right angle or an obtuse angle.
USING STRUCTURE TUV is a \(30^{\circ}-60^{\circ}-90^{\circ}\) triangle, where two vertices are \(\mathrm{U}(3,-1)\) and \(\mathrm{V}(-3,-1)\) . UV is the hypotenuse, and point \(T\) is in Quadrant 1 Find the coordinates of T.
THOUGHT PROVOKINgQne of the following infnite series represents six and the other one represents cos \(x\) (where \(x\) is measured in radians). Which is which? Justify your answer. Then use each series to approximate the sine and cosine of \(\frac{\pi}{6}\) . (Hints: \(\pi=180^{\circ} ; 5 !=5 \cdot 4 \cdot 3.2 \cdot 1 ;\) Find the values that the sine and cosine ratios approach as the angle measure approaches zero.) $$ \begin{array}{l}{\text { a. } x-\frac{x^{3}}{3 !} \quad \frac{x^{5}}{5 !}-\frac{x^{7}}{7 !}} \\ {\text { b. } 1-\frac{x^{2}}{2 !} | \frac{x^{4}}{4 !}-\frac{x^{6}}{6 !}}\end{array} $$
MULTIPLE REPRESENTATIONSu are standing on a cliff above an ocean. You see a sailboat from your vantage point 30 feet above the ocean. a. Draw and label a diagram of the situation. b. Make a table showing the angle of depression and the length of your line of sight. Use the angles \(40^{\circ}\) , \(50^{\circ}, 60^{\circ}, 70^{\circ},\) and \(80^{\circ}\) . c. Graph the values you found in part (b), with the angle measures on the \(\mathrm{x}\) -axis. dredict the length of the line of sight when the angle of depression is \(30^{\circ}\) .
In Exercises 27–32, tell whether you would use the Law of Sines, the Law of Cosines, or the Pythagorean Theorem (Theorem 9.1) and trigonometric ratios to solve the triangle with the given information. Explain your reasoning. Then solve the triangle. $$\mathrm{m} \angle \mathrm{B}=98^{\circ}, \mathrm{m} \angle \mathrm{C}=37^{\circ}, \mathrm{a}=18$$
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