Chapter 4: Problem 42
Solve the equation. $$-2(8-y)=-6 y$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 4: Problem 42
Solve the equation. $$-2(8-y)=-6 y$$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Two geometric figures are ________ if and only if there is a rigid motion or a composition of rigid motions that moves one of the figures onto the other.
Prove the Reflections in Parallel Lines Theorem (Theorem 4.2). Given \(\quad\) A reflection in line\(^\ell\) \(\operatorname{maps} \overline{J K}\) to \(\overline{J^{\prime} K^{\prime}},\) a reflection in line m maps \(\overline{\mathrm{J}^{\prime} \mathrm{K}^{\prime}}\) to \(\overline{\mathrm{J}^{\prime \prime} \mathrm{K}^{\prime \prime}}\) and\(^\ell\) m. Prove \(\quad\) a. \(\overline{\mathrm{KK}^{\prime \prime}}\) is perpendicular to \(\ell\) and \(\mathrm{m}\) \(\qquad\) \(\quad\) b. \(\mathrm{KK}^{\prime \prime}=2 \mathrm{d},\) where d is the distance between \(\ell\) and \(\mathrm{m} .\)
Last year, the track team's yard sale earned \(\$ 500 .\) This year, the yard sale earned \(\$ 625 .\) What is the percent of increase?
ERROR ANALYSIS In Exercises 25 and 26 of \(\overline{\mathrm{CD}}\) are \(\mathrm{C}(\mathrm{I} 1,1)\) and \(\mathrm{D}(2,3)\) . Describe and correct the error in Inding the coordinates of the vertices of the image after a rotation of \(270^{\circ}\) about the origin. \(C(\square 1,1) \rightarrow C^{\prime}(1,1)\) \(D(2,3) \rightarrow D^{\prime}(2,3)\)
MAKING AN ARGUMENT A translation maps GH to G'H'. Your friend claims that if you draw segments connecting G to G' and H to H', then the resulting quadrilateral is a parallelogram. Is your friend correct? Explain your reasoning.
What do you think about this solution?
We value your feedback to improve our textbook solutions.