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Count the possible combinations of \(r\) letters chosen from the given list. (See Example 4 .) $$\mathrm{D}, \mathrm{E}, \mathrm{F}, \mathrm{G}, \mathrm{H} ; r=4$$

Short Answer

Expert verified
The number of combinations of 4 letters chosen from the given list is 5.

Step by step solution

01

Understanding Combinations

In combinatorics, a combination is a way of selecting items from a larger set where the order of selection does not matter. Combination is given by formula \(C(n, r) = \frac{n!}{r!(n-r)!}\), where 'n!' denotes n factorial, r is the number of items to select and n is the total number of items.
02

Identify n and r

In this problem, we are asked to select 4 letters (so r=4) out of a set of 5 letters D, E, F, G, H (so n=5). We are thus interested in \(C(5, 4)\).
03

Calculate the number of combinations

Apply the formula for combinations, \(C(5, 4) = \frac{5!}{4!(5-4)!} = \frac{5}{1} = 5\). Therefore, there are 5 combinations of 4 letters that can be chosen from the set {D, E, F, G, H}.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combination Formula
In combinatorics, the combination formula is crucial for calculating the number of ways to choose a subset of items from a larger set when the order of selection does not matter. This concept is symbolically represented by the notation \( C(n, r) \), also known as the binomial coefficient. To understand this concept, let's take a closer look at its components.

The combination formula is \( C(n, r) = \frac{n!}{r!(n-r)!} \), where \( n! \) represents the factorial of \( n \), \( r \) is the number of items you want to select, and \( n-r \) essentially stands for the number of items which will not be selected. The factorial in the denominator accounts for removing the repeated counts that arise from arranging \( r \) items in different orders since their sequence is irrelevant in combinations.

Using the given exercise as an example, the task was to find the number of ways to choose 4 letters out of 5. By applying the combination formula, the solution shows that there are 5 possible combinations. What this effectively means is that, unlike permutations, flipping the order of the selected letters does not create a new combination; 'DEFG' is the same as 'GFED' in the context of combinations.
Factorial Notation
Central to understanding combinatorics is the concept of factorial notation. Often used in permutations and combinations, the factorial of a non-negative integer \( n \), denoted by \( n! \), is the product of all positive integers less than or equal to \( n \). For instance, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \). There's also a special case where the factorial of zero, \( 0! \), is defined to be 1.

Factorials grow extremely rapidly with increasing values of \( n \), which makes them pivotal in calculating the vast number of ways objects can be arranged or selected. Interestingly, the concept of factorial is simple to understand yet opens the door to solving complex combinatorial problems, such as the exercise example given where the term \( 5! \) is a stepping stone to finding the solution.
Permutations and Combinations
While both permutations and combinations are fundamental concepts in combinatorics, it is important to distinguish between the two. Permutations are about arranging items in a specific order, where the order is important and does make a difference. In stark contrast, combinations involve selecting items without regard for the order.

Consider a scenario where you want to determine how many different 2-letter arrangements can be made from the letters A, B, and C. Using permutations, there are six possibilities because order matters: AB, BA, AC, CA, BC, and CB. But if we look at combinations, where the order does not matter, there would only be three possibilities: AB, AC, and BC.

This difference is essential when students solve exercises like the one provided. While permutations would consider 'DEFG' and 'GFED' as distinct entities, combinations treat them as identical since the selection group remains the same—this nuanced understanding is critical when tackling combinatorial problems and can be a common source of confusion among students.

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