Chapter 10: Problem 4
Solve for \(x\) in each of the following proportions. $$\frac{x}{3}=\frac{9}{10}$$
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Chapter 10: Problem 4
Solve for \(x\) in each of the following proportions. $$\frac{x}{3}=\frac{9}{10}$$
These are the key concepts you need to understand to accurately answer the question.
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Suppose that Uncle Albert's arm span is 3 feet and that Alabaster's arm span is 15 inches. Change Alabaster's measurement to feet and find the ratio of their arm spans. Express the ratio in decimal form.
Example: 12 and 15 $$ \begin{aligned} \text { Solution: } \frac{12}{x} &=\frac{x}{15} \\ x^{2} &=180 \\ x &=\sqrt{180} \text { (because } x \text { is positive }) \\ &=\sqrt{36} \cdot 5 \\ &=6 \sqrt{5} \end{aligned} $$ 3 and 27
Suppose that Uncle Albert's arm span is 3 feet and that Alabaster's arm span is 15 inches. Does it seem correct to say that the ratio of their respective arm spans is \(\frac{3}{15}\) or \(\frac{1}{5} ?\)
Write the proportion that results from dividing both sides of the equation $$ 5 x=12 y $$ by each of the following quantities. Example: \(5 y\) Solution: \(\frac{5 x}{5 y}=\frac{12 y}{5 y},\) and so \(\frac{x}{y}=\frac{12}{5}\) $$60$$
Tell what can be done to both sides of the equation $$ a d=b c $$ to get each of the following equations. $$\text { Example: } \frac{a}{b}=\frac{c}{d}$$ $$ \begin{array}\text{Answer: Divide} \text{ by } { bd } \\ \frac{a d}{b d}=\frac{b c}{b d}, \text { and so } \frac{a}{b}=\frac{c}{d} \end{array} $$ $$\frac{d}{c}=\frac{b}{a}$$
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