Chapter 23: Problem 455
Show that the median of any triangle separates the triangle into two regions of equal area.
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 23: Problem 455
Show that the median of any triangle separates the triangle into two regions of equal area.
These are the key concepts you need to understand to accurately answer the question.
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Let the two congruent sides of an isosceles triangle have lengths \(\mathrm{a}\), and let the included angle have measure \(\theta\). Choosing the third side as a base, let the corresponding altitude be of length \(\mathrm{r}\). Prove that the area enclosed by the triangle is given by the formula \(\mathrm{A}=\mathrm{r}^{2} \tan \theta / 2\)
The area of a rhombus is 90 , and one diagonal is 10 . Find the length of the other diagonal.
Let the congruent sides of an isosceles triangle have lengths \(\mathrm{r}\), and let the included angle have measure \(\theta\). Prove that the area enclosed by the triangle is given by \(\mathrm{A}=(1 / 2) \mathrm{r}^{2} \sin \theta\).
A parallelogram whose base is represented by \(\mathrm{x}+4\) and whose altitude is represented by \(\mathrm{x}-1\) is equivalent to a square whose side is 6 . Find the base and altitude of the parallelogram.
If two triangles have congruent bases, then the ratio of their areas equals the ratio of the lengths of their altitudes.
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