/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Sei \(\emptyset \neq D \subset C... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sei \(\emptyset \neq D \subset C\) offen. Die stetige Funktion \(f: D \longrightarrow \mathbb{C}, z \longmapsto \bar{z}\), besitzt in \(D\) keine Stammfunktion.

Short Answer

Expert verified
The function \(f(z) = \overline{z}\) has no antiderivative in \(D\) because it is not holomorphic.

Step by step solution

01

Understand the Problem

We are given that function \(f(z) = \overline{z}\) is continuous on an open subset \(D\) of \(\mathbb{C}\), and we need to determine if it has an antiderivative on \(D\). An antiderivative of a function \(g(z)\) is a function \(G(z)\) satisfying \(G'(z) = g(z)\).
02

Recall a Property of Antiderivatives

Recall that if a function has an antiderivative, it must be analytic, or holomorphic, over the domain. A function is analytic if it is differentiable at every point in its domain.
03

Examine the Function's Differentiability

Evaluate \(f(z) = \overline{z}\). The function \(f\) is not holomorphic because it does not satisfy the Cauchy-Riemann equations, which are necessary for differentiability in the complex plane.
04

Verify Cauchy-Riemann Equations Failure

Set \(z = x + iy\) and \(\overline{z} = x - iy\). For \(f(z)\) to be holomorphic, it must satisfy \(\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y}\) and \(\frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x}\). Here, \(u(x,y) = x\) and \(v(x, y) = -y\). Calculating the partial derivatives: \(\frac{\partial u}{\partial x} = 1\), \(\frac{\partial v}{\partial y} = -1\), so this fails. Hence, \(f\) is not holomorphic.
05

Conclusion

Since \(f(z) = \overline{z}\) is not holomorphic on \(D\), it cannot have an antiderivative on \(D\). This confirms the result that \(f\) does not possess a primitive in \(D\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Antiderivative
An antiderivative, also known as a primitive or indefinite integral, is a function that reverses the process of differentiation. For a given function \( g(z) \), an antiderivative is a function \( G(z) \) such that the derivative of \( G(z) \) is \( g(z) \).
In mathematical terms, this is expressed as \( G'(z) = g(z) \). Finding an antiderivative is an integral part of solving problems in calculus and complex analysis.
However, not all functions have antiderivatives. In the context of complex functions, a function must typically be holomorphic on the domain to possess an antiderivative.
This brings us to the characteristic that for a complex function to have an antiderivative, it should be analytic in that region. For the function \( f(z) = \overline{z} \), the lack of an antiderivative stems from its failure to meet this condition of being holomorphic.
Holomorphic Functions
Holomorphic functions play a crucial role in complex analysis, similar to differentiable functions in real analysis. A function is holomorphic if it is complex differentiable at every point of its domain, which often implies that it is analytic.
This means it can be represented by a power series around any point within its domain.
Analytic functions are smooth and have no abrupt changes or breaks in their behaviour.
  • Continuity: A holomorphic function is continuous, meaning there are no jumps or breaks as inputs change smoothly.
  • Differentiability: Beyond being continuous, holomorphic functions are differentiable, allowing them to have a derivative at every point in their domain.
  • Power Series Representation: Holomorphic functions can be expressed as a convergent power series, making them very predictable and easy to handle in calculations.
Thus, the property of being holomorphic is stronger than just being continuous or differentiable. For \( f(z) = \overline{z} \), the function is continuous but not holomorphic, as it doesn't satisfy the complex differentiability condition.
Cauchy-Riemann Equations
The Cauchy-Riemann equations are a set of two partial differential equations that provide a necessary condition for a function to be holomorphic.
These equations link the real and imaginary parts of a complex function.
If we write a complex function \( f(z) = u(x, y) + iv(x, y) \), where \( u \) and \( v \) are the real and imaginary parts respectively, the Cauchy-Riemann equations are:
\( \frac{\partial u}{\partial x} = \frac{\partial v}{\partial y} \) and \( \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x} \).
These equations must hold at every point in a domain for a function to be holomorphic.
  • The equations essentially ensure the matching of changes in both parts to maintain differentiability.
  • They are crucial for checking the analyticity and smoothness of a function in the complex plane.
In the analysis of \( f(z) = \overline{z} \), substituting gives \( u(x, y) = x \) and \( v(x, y) = -y \).
Upon calculation, \( \frac{\partial u}{\partial x} = 1 \) does not equal \( \frac{\partial v}{\partial y} = -1 \); thereby failing the Cauchy-Riemann criteria, proving \( f \) is not holomorphic.
Complex Differentiability
Complex differentiability is a concept that mirrors the idea of differentiability in real analysis but requires stricter conditions.
For a complex function \( f \) to be differentiable at a point \( z_0 \), the limit
\[ \lim_{h \to 0} \frac{f(z_0 + h) - f(z_0)}{h} \]
must exist and be the same no matter which direction \( h \) approaches 0 in the complex plane.
This is more stringent than real differentiability because it involves all possible directions of approach around the point.
  • Directional Consistency: In the complex plane, a function must behave consistently in every direction to be differentiable.
  • Smooth Behavior: This consistency ensures smoothness and continuity without irregularities.
A function that is complex differentiable at all points of its domain is holomorphic.
For \( f(z) = \overline{z} \), the function fails this test of differentiability due to its failure to meet the Cauchy-Riemann equations, affirming it is not holomorphic and hence, not complex differentiable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.