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True or False: The mean of the sampling distribution of \(\hat{p}\) is \(p\)

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Step by step solution

01

Understand the Problem

We need to determine whether the mean of the sampling distribution of \(\frac{\text{count of successes}}{\text{sample size}}\), denoted as \(\text{\hat{p}}\), is equal to the population proportion \( p \).
02

Know the Definition

In sampling distribution theory, if \( p \) is the true proportion of successes in the population, then the mean of the sampling distribution of \( \text{\hat{p}} \) (the sample proportion) is equal to \( p \). This is a property of the sample proportion.
03

Conclude

Based on the definition from the previous step, the statement is indeed true. The mean of the sampling distribution of \( \text{\hat{p}} \) is equal to the true proportion \( p \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sample proportion
The concept of a sample proportion is foundational in statistics. When we deal with proportions, we are often interested in the ratio of a certain characteristic within a sample group. For example, if we want to know the proportion of left-handed students in a classroom of 30, and we find 6 left-handed students, the sample proportion, denoted as \(\text{\hat{p}}\), would be \(\frac{6}{30} = 0.2\). This means 20% of the sample is left-handed.
Sample proportions are used to make inferences about the population from which the sample is drawn.
They are particularly useful when it is impractical or impossible to survey the entire population.
Remember, a sample proportion is a point estimate of the population proportion, giving us a snapshot of what the true proportion might be.
mean of sampling distribution
The mean of the sampling distribution of a statistic, such as the sample proportion \(\text{\hat{p}}\), is a central concept in inferential statistics. The sampling distribution itself is the probability distribution of a statistic obtained from a large number of samples drawn from a specific population.
For the sample proportion, the mean of this sampling distribution is particularly simple—it equals the population proportion \(\text{p}\). This is because, on average, our sample proportions should cluster around the true population proportion if we repeatedly take random samples.
Mathematically, if \(\text{p}\) is the population proportion, then \(\text{E}(\hat{p}) = p\). This property is essential because it assures us that our sample proportion is an unbiased estimator of the population proportion.
In essence, the mean of the sampling distribution of \(\hat{p}\) gives us the true parameter towards which our sample statistics converge as we increase our sample size.
population proportion
The population proportion, denoted as \(p\), is a key parameter in statistics representing the true fraction of a population that possesses a certain characteristic. In the left-handed students example, if the true proportion of left-handed students in a larger region is 20%, then \(p = 0.2\).
Understanding the population proportion is crucial because it is the benchmark against which we compare our sample proportion \(\hat{p}\).
We use statistical methods to estimate \(p\) from sample data since obtaining data from the entire population is often not feasible.
The accuracy of our estimation improves with the size of our sample. Larger sample sizes tend to provide better approximations of the population proportion. When we understand that the mean of the sampling distribution of \(\hat{p}\) is equal to \(p\), we gain confidence in using sample data to make population-level inferences.

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Most popular questions from this chapter

The following data represent the ages of the winners of the Academy Award for Best Actor for the years \(1999-2004\) $$\begin{array}{lr} 2004: \text { Jamie Foxx } & 37 \\ \hline 2003 \text { - Sean Penn } & 43 \\ \hline 2002 \text { . Adrien Brody } & 29 \\ \hline 2001: \text { Denzel Washington } & 47 \\ \hline 2000 \text { . Russell Crowe } & 36 \\ \hline 1999 \text { . Kevin Spacey } & 40 \end{array}$$ (a) Compute the population mean, \(\mu\) (b) List all possible samples with size \(n=2\). There should be \(_{6} C_{2}=15\) samples. (c) Construct a sampling distribution for the mean by listing the sample means and their corresponding probabilities. (d) Compute the mean of the sampling distribution. (e) Compute the probability that the sample mean is within 3 years of the population mean age. (f) Repeat parts \((b)-(e)\) using samples of size \(n=3\) Comment on the effect of increasing the sample size.

Burger King's Drive-Through Suppose cars arrive at Burger King's drive-through at the rate of 20 cars every Hour between 12: 00 noon and 1: 00 P.M. A random sample \- of 40 one-hour time periods between 12: 00 noon and 1: 00 P.M. is selected and has 22.1 as the mean number of cars erriving. (a) Why is the sampling distribution of \(\bar{x}\) approximately normal? (b) What is the mean and standard deviation of the sampling distribution of \(\bar{x}\) assuming \(\mu=20\) and \(\boldsymbol{\sigma}=\sqrt{20}\) (c) What is the probability that a simple random sample of 40 one-hour time periods results in a mean of at least 22.1 cars? Is this result unusual? What might we conclude?

A nationwide study in 2003 indicated that about \(60 \%\) of college students with cell phones send and receive text messages with their phones. Suppose a simple random sample of \(n=1136\) college students with cell phones is obtained. (Source: promomagazine.com) (a) Describe the sampling distribution of \(\hat{p},\) the sample proportion of college students with cell phones who send or receive text messages with their phones. (b) What is the probability that 665 or fewer college students in the sample send and receive text messages with their cell phones? Is this result unusual? (c) What is the probability that 725 or more college students in the sample send and receive text messages with their cell phone? Is this result unusual?

What happens to the standard deviation of \(\hat{p}\) as the sample size increases? If the sample size is increased by a factor of \(4,\) what happens to the standard deviation of \(\hat{p} ?\)

In this section, we assumed that the sample size was less than \(5 \%\) of the size of the population. When sampling without replacement from a finite population in which \(n>0.05 N,\) the standard deviation of the distribution of \(\hat{p}\) is given by $$\sigma_{p}=\sqrt{\frac{\hat{p}(1-\hat{p})}{n-1} \cdot\left(\frac{N-n}{N}\right)}$$ where \(N\) is the size of the population. Suppose a survey is conducted at a college having an enrollment of 6,502 students. The student council wants to estimate the percentage of students in favor of establishing a student union. In a random sample of 500 students, it was determined that 410 were in favor of establishing a student union. (a) Obtain the sample proportion, \(\hat{p},\) of students surveyed who favor establishing a student union. (b) Calculate the standard deviation of the sampling distribution of \(\hat{p}\)

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