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Find the indicated areas. For each problem, be sure to draw a standard normal curve and shade the area that is to be found. Determine the area under the standard normal curve that lies to the right of (a) \(Z=-3.01\) (b) \(Z=-1.59\) (c) \(Z=1.78\) (d) \(Z=3.11\)

Short Answer

Expert verified
(a) 0.9987 (b) 0.9441 (c) 0.0375 (d) 0.0009

Step by step solution

01

- Identify the Z-values

The given Z-values for which we need to find the areas under the standard normal curve are: (a) \( Z = -3.01 \) (b) \( Z = -1.59 \) (c) \( Z = 1.78 \) (d) \( Z = 3.11 \).
02

- Understand the Area to the Right

To find the area to the right of a given Z-value, use the standard normal distribution table or a Z-table. This provides the area to the left of the Z-value, so subtract this value from 1 to get the area to the right.
03

- Find Area for (a) Z = -3.01

Look up the Z-value \( Z = -3.01 \) in the Z-table. The area to the left is approximately 0.0013. Therefore, the area to the right is \[ 1 - 0.0013 = 0.9987 \].
04

- Find Area for (b) Z = -1.59

Look up the Z-value \( Z = -1.59 \) in the Z-table. The area to the left is approximately 0.0559. Therefore, the area to the right is \[ 1 - 0.0559 = 0.9441 \].
05

- Find Area for (c) Z = 1.78

Look up the Z-value \( Z = 1.78 \) in the Z-table. The area to the left is approximately 0.9625. Therefore, the area to the right is \[ 1 - 0.9625 = 0.0375 \].
06

- Find Area for (d) Z = 3.11

Look up the Z-value \( Z = 3.11 \) in the Z-table. The area to the left is approximately 0.9991. Therefore, the area to the right is \[ 1 - 0.9991 = 0.0009 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-values
Z-values, or Z-scores, provide a way to express the position of a data point relative to the mean of a standard normal distribution. In a standard normal distribution, the mean is 0, and the standard deviation is 1. The Z-value tells us how many standard deviations away from the mean a particular value is.

Positive Z-values indicate the distance above the mean, while negative Z-values represent the distance below the mean. For instance, a Z-value of 1.78 means the value is 1.78 standard deviations above the mean, while a Z-value of -1.59 indicates it is 1.59 standard deviations below the mean.

Z-values are vital for comparing individual data points from different normal distributions as they standardize scores, allowing comparisons on a single scale.
Area Under the Curve
The area under the curve in a standard normal distribution represents probabilities. The total area under the standard normal curve equals 1, or 100%.

When working with Z-values, we often need to find the probability of a value being less than or greater than the Z-value. This probability corresponds to the area under the curve.

In the standard normal distribution:
  • To find the area to the left of a Z-value, we use the area given by the Z-table directly.
  • To find the area to the right of a Z-value, we subtract the area to the left from 1. This is because the total area under the curve is always 1.
Let's consider specific examples:

If you have a Z-value of -3.01, the area to the left is 0.0013. Therefore, the area to the right (probability of a value being greater than -3.01) is 1 - 0.0013 = 0.9987. Similarly, for a Z-value of 3.11, the area to the left is 0.9991, and the area to the right is 0.0009. Understanding these areas helps in determining the probability or significance of a data point within a standard normal distribution.
Z-table
A Z-table, or standard normal table, lists the cumulative probability of a standard normal Z-score. It shows the area under the standard normal curve to the left of a given Z-value.

To use the Z-table:
  • Identify the Z-value you are interested in.
  • Locate the row that corresponds to the first two digits of the Z-value.
  • Find the precise column by identifying the second decimal digit of the Z-value.
  • Read the cumulated area to the left of this Z-value from the table.
For example, to find the area for Z = 1.78:
  • Look at the row for 1.7.
  • Then find the column for 0.08.
  • The intersection gives you an area of 0.9625, which is the area to the left of Z = 1.78.
This area (0.9625) means there is a 96.25% probability that a value is less than 1.78 standard deviations above the mean. For areas to the right, as discussed, subtract this value from 1 (like 1 - 0.9625 = 0.0375). Mastering the Z-table helps you efficiently find probabilities and understand the distribution of variables.

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Most popular questions from this chapter

The Empirical Rule The Empirical Rule states that about \(68 \%\) of the data in a bell-shaped distribution lies within 1 standard deviation of the mean. This means about \(68 \%\) of the data lie between \(Z=-1\) and \(Z=1\) Verify this result. Verify that about \(95 \%\) of the data lie within 2 standard deviations of the mean. Finally, verify that about \(99.7 \%\) of the data lie within 3 standard deviations of the mean.

Find the indicated probability of the standard normal random variable \(Z\). $$P(Z<1.93)$$

According to a USA Today "Snapshot," \(3 \%\) of Americans surveyed lie frequently. Suppose you conduct a survey of 500 college students and find that 20 of them lie frequently. (a) Compute the probability that, in a random sample of 500 college students, at least 20 lie frequently, assuming the true percentage is \(3 \%\) (b) Does this result contradict the USA Today "Snapshot"? Explain.

The following data represent the relative frequencies of live multiple- delivery births (three or more babies) in 2002 for women 15 to 44 years old. Suppose the ages of multiple-birth mothers are approximately normally distributed with \(\mu=31.77\) years and standard deviation \(\sigma=5.19\) years. (a) Compute the proportion of multiple-birth mothers in each class by finding the area under the normal curve. (b) Compare the proportion to the actual proportions. Are you convinced that the ages of multiple-birth mothers are approximately normally distributed?

Find the indicated probability of the standard normal random variable \(Z\). $$P(Z<-0.61)$$

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