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Suppose you have just received a shipment of 100 televisions. Although you don't know this, 6 are defective. To determine whether you will accept the shipment, you randomly select 5 televisions and test them. If all 5 televisions work, you accept the shipment; otherwise, the shipment is rejected. What is the probability of accepting the shipment?

Short Answer

Expert verified
The probability of accepting the shipment is \( \frac{\binom{94}{5}}{\binom{100}{5}} \).

Step by step solution

01

Determine the Total Combinations

First, find the total number of ways to select 5 televisions out of 100. This can be determined using a combination formula: \[ \binom{100}{5} = \frac{100!}{5!(100-5)!} \]
02

Determine the Probability of Choosing Non-Defective TVs

Next, consider the number of non-defective televisions. Since 6 are defective, the remaining are 94 non-defective televisions. We need to find the number of ways to select 5 non-defective televisions from the 94 non-defective televisions: \[ \binom{94}{5} = \frac{94!}{5!(94-5)!} \]
03

Calculate the Probability of Accepting the Shipment

Find the probability that all selected televisions are non-defective by dividing the number of favorable outcomes by the total outcomes: \[ P(\text{Accept}) = \frac{\binom{94}{5}}{\binom{100}{5}} \]
04

Simplify the Combination Expressions

Simplify the combinations calculated in Steps 1 and 2 for easier computation, if necessary.
05

Compute and Interpret the Final Probability

Finally, compute the numerical value of the probability using simplified numbers or a calculator.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinations
When faced with problems involving selections, we often use combinations. Combinations help us determine how many ways we can choose a subset of items from a larger set, without regard for the order of selection. The formula for combinations is: \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \). In this problem, we want to know how many ways we can choose 5 televisions from 100. We use the combination formula to find this: \( \binom{100}{5} = \frac{100!}{5!(100-5)!} \). This value represents all possible ways to select 5 TVs out of the total 100.
Understanding and using combinations is crucial because it allows us to count possible selections and focus on computing probabilities effectively.
Non-Defective Items
Non-defective items are those that work perfectly. In our shipment, out of the 100 televisions, 94 are non-defective. When solving the problem, it's important to realize how many non-defective TVs are there because our goal is to accept the shipment if all tested TVs work. This means we must look at how many ways we can select 5 non-defective TVs from the 94 non-defective ones: \( \binom{94}{5} = \frac{94!}{5!(94-5)!} \). Calculating this helps us identify the favorable outcomes needed to accept the shipment.
Knowing the number of non-defective items lets us accurately set up our probability calculations and make decisions based on reliable expectations.
Probability Calculation
Probability helps us quantify the likelihood of an event occurring. In this context, we want to find the probability that the 5 TVs selected are all non-defective. This is expressed as: \( P(\text{Accept}) = \frac{\binom{94}{5}}{\binom{100}{5}} \). The numerator represents the number of favorable outcomes (choosing 5 non-defective TVs), and the denominator represents the total possible outcomes (choosing any 5 TVs out of 100).
Calculating this ratio gives us the probability that can be interpreted to inform our decision about accepting the shipment. This step integrates our earlier steps, consolidating them into one clear probabilistic statement.
Shipment Acceptance
Shipment acceptance depends on the outcome of our probability calculation. This rule—accepting shipments only if all tested items are non-defective—ensures quality control. Understanding and applying this rule involves calculating the probability that no defective TVs are included in the selection. If this probability is high, the shipment is likely accepted. Conversely, a low probability means rejecting the shipment.
By setting clear acceptance criteria based on non-defective items, businesses can maintain product quality and meet customer standards.
Defective Items
Defective items are those that do not work as expected. In our problem, 6 out of the 100 televisions are defective. Their presence affects the acceptance of the shipment because if any defective TVs are selected, the entire shipment is rejected. The challenge is balancing the presence of defective items against the total, which directly impacts the probability of drawing a set of 5 TVs with no defective ones.
Considering defective items in probability problems emphasizes the importance of both quality control and accurate probability assessment to make informed business decisions.

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Most popular questions from this chapter

A flush in the card game of poker occurs if a player gets five cards that are all the same suit (clubs, diamonds, hearts, or spades). Answer the following questions to obtain the probability of being dealt a flush in five cards. (a) We initially concentrate on one suit, say clubs. There are 13 clubs in a deck. Compute \(P\) (five clubs) \(=\) \(P(\) first card is clubs and second card is clubs and third card is clubs and fourth card is clubs and fifth card is clubs). (b) A flush can occur if we get five clubs or five diamonds or five hearts or five spades. Compute \(P\) (five clubs or five diamonds or five hearts or five spades). Note the events are mutually exclusive.

List all the permutations of five objects \(a, b, c, d,\) and \(e\) taken two at a time without repetition. What is \(_{5} P_{2} ?\)

Suppose that \(E\) and \(F\) are two events and that \(P(E \text { and } F)=0.21\) and \(P(E)=0.4 .\) What is \(P(F | E) ?\)

The probability that a randomly selected individual in the United States 25 years and older has at least a bachelor's degree is \(0.272 .\) The probability that an individual in the United States 25 years and older has at least a bachelor's degree, given that the individual is Hispanic, is 0.114. Are the events "bachelor's degree" and "Hispanic" independent? (Source: Educational Attainment in the United States, 2003. U.S. Census Bureau, June 2004 )

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