/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 In how many ways can the top 2 h... [FREE SOLUTION] | 91Ó°ÊÓ

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In how many ways can the top 2 horses finish in a 10 -horse race?

Short Answer

Expert verified
90 ways

Step by step solution

01

Identify the problem

Determine the number of ways to arrange the top 2 finishers out of a group of 10 horses.
02

Understand permutations

Since the order of finishers matters (i.e., 1st place and 2nd place are different), we will use permutations. The formula for permutations of selecting 2 items out of 10 is given by: \[ P(n, r) = \frac{n!}{(n-r)!} \]where \(n\) is the total number of items and \(r\) is the number of items to choose.
03

Apply the permutation formula

Substitute \(n = 10\) and \(r = 2\) into the formula: \[ P(10, 2) = \frac{10!}{(10-2)!} = \frac{10!}{8!} \]
04

Calculate the values

Simplify the factorials: \[ 10! = 10 \times 9 \times 8! \]Thus, \[ P(10, 2) = \frac{10 \times 9 \times 8!}{8!} = 10 \times 9 = 90 \]
05

Conclusion

There are 90 different ways for the top 2 horses to finish in a 10-horse race.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arrangement
An arrangement refers to the specific order in which items are organized. In the context of our exercise, an arrangement deals with the order in which the top 2 horses finish in a 10-horse race.

It’s essential to understand that the sequence matters here. For example, Horse A finishing first and Horse B finishing second is a different arrangement from Horse B finishing first and Horse A second.

We use permutations to calculate such arrangements because permutations account for the order of items. The more items you have or the more positions you want to arrange them in, the number of possible arrangements increases significantly.

Understanding the concept of arrangement will help us see why the order is critical and why using permutations is the appropriate method in these types of problems.
Factorial
A factorial, denoted by an exclamation mark (!), is the product of all positive integers up to a given number. For example, the factorial of 5 (written as 5!) is calculated as:

\[5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\]

Factorials are helpful in permutations because they help us compute the possible ways to arrange a set of items.

In our exercise, we used the factorial to calculate permutations. The formula is \[ P(n, r) = \frac{n!}{(n-r)!} \]where \( n \) is the total number of items and \( r \) is the number of items to choose.

By substituting the values \( n = 10 \) and \( r = 2 \), we simplify like this:
\[ 10! = 10 \times 9 \times 8 \times ... \times 1 \] \[ \frac{10!}{8!} = \frac{10 \times 9 \times 8!}{8!} = 10 \times 9 = 90 \] Factorials become more intuitive with practice and are a vital part of combinatorics and permutations.
Combinatorics
Combinatorics is a branch of mathematics that studies the counting, arrangement, and combination of objects. It helps us understand how to count the different ways objects can be arranged or selected.

Permutations and combinations are the two fundamental concepts in combinatorics.
  • Permutations: Concerned with arrangements where order matters.
  • Combinations: Concerned with selections where order does not matter.
In our exercise, we looked at permutations because the order in which the horses finish matters.

Understanding combinatorics gives students powerful tools for counting and arranging different objects, which appears in various real-life scenarios and other fields of mathematics, like graph theory and probability.

By knowing the basics of combinatorics, students can solve more complex counting problems and develop better problem-solving skills.

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Most popular questions from this chapter

Find the value of each permutation. $$_{9} P_{4}$$

The local golf store sells an "onion bag" that contains 80 "experienced" golf balls. Suppose the bag contains 35 Titleists, 25 Maxflis, and 20 Top-Flites. (a) What is the probability that a randomly selected golf ball is a Titleist? (b) What is the probability that a randomly selected golf ball is a Top-Flite?

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