/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 A bag of 30 tulip bulbs purchase... [FREE SOLUTION] | 91Ó°ÊÓ

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A bag of 30 tulip bulbs purchased from a nursery contains 12 red tulip bulbs, 10 yellow tulip bulbs, and 8 purple tulip bulbs. (a) What is the probability that two randomly selected tulip bulbs are both red? (b) What is the probability that the first bulb selected is red and the second yellow? (c) What is the probability that the first bulb selected is yellow and the second is red? (d) What is the probability that one bulb is red and the other yellow?

Short Answer

Expert verified
(a) \( \frac{22}{145} \), (b) \( \frac{4}{29} \), (c) \( \frac{4}{29} \), (d) \( \frac{8}{29} \)

Step by step solution

01

Calculate the total number of tulip bulbs

The total number of tulip bulbs in the bag is given. Add up the number of red, yellow, and purple tulip bulbs: Total = 12 (red) + 10 (yellow) + 8 (purple) = 30 bulbs
02

Calculate the probability of selecting two red tulip bulbs (Part a)

The probability of selecting the first red bulb is \( \frac{12}{30} \). After selecting the first red bulb, there are now 11 red bulbs left and the total number of bulbs is 29. The probability of selecting a second red bulb is then \( \frac{11}{29} \): P(Two red) = \( \frac{12}{30} \times \frac{11}{29} = \frac{132}{870} = \frac{44}{290} = \frac{22}{145} \)
03

Calculate the probability of the first bulb being red and the second yellow (Part b)

The probability of the first bulb being red is \( \frac{12}{30} \). After picking a red bulb, there are 10 yellow bulbs out of 29 remaining bulbs. So, the probability of picking a yellow bulb second is \( \frac{10}{29} \): P(Red first, Yellow second) = \( \frac{12}{30} \times \frac{10}{29} = \frac{120}{870} = \frac{4}{29} \)
04

Calculate the probability of the first bulb being yellow and the second red (Part c)

The probability of the first bulb being yellow is \( \frac{10}{30} \). After picking a yellow bulb, there are 12 red bulbs out of 29 remaining bulbs. So, the probability of picking a red bulb second is \( \frac{12}{29} \): P(Yellow first, Red second) = \( \frac{10}{30} \times \frac{12}{29} = \frac{120}{870} = \frac{4}{29} \)
05

Calculate the probability that one bulb is red and the other is yellow (Part d)

The probability that one bulb is red and the other is yellow is the sum of the probability of the first bulb being red and the second being yellow plus the probability of the first bulb being yellow and the second being red: P(One red and one yellow) = P(Red first, Yellow second) + P(Yellow first, Red second) P(One red and one yellow) = \( \frac{4}{29} + \frac{4}{29} = \frac{8}{29} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

combinations
Combinations help us determine how many ways we can choose items from a group without caring about the order. In probability, combinations are often used when we want to select multiple items from a set without replacement.
For example, let's say we have 30 tulip bulbs and we want to find how many ways we can select 2 bulbs from them. The formula for combinations is given by \( \text{C} (n, k) = \frac{n!}{k! (n - k)!} \).
Here, 'n' represents the total number of items and 'k' is the number of items to choose.
However, in our specific problem, calculating combinations directly isn't necessary since we use probabilities in steps to find our answers. Remember, combinations are beneficial when we need to know the total number of ways to pick items without regard to the order in which they are picked.
conditional probability
Conditional probability is the probability of an event happening given that another event has already happened. We denote the conditional probability of B occurring given that A has occurred as \( P(B|A) \).
In this exercise, when we select the second tulip bulb, the probability changes because the first bulb has already been picked. For instance, picking two red tulips involves calculating the probability of picking a red one first and then another red one immediately after: \( P(\text{Red}_1) \times P(\text{Red}_2|\text{Red}_1) = (\frac{12}{30})(\frac{11}{29}) \).
This calculation effectively uses the concept of conditional probability. The key idea here is that the second event's probability (picking another red tulip) is affected by the outcome of the first event (picking the first red tulip). This dependency makes conditional probability so critical in these problems.
multiplication rule in probability
The multiplication rule is essential for finding the probability of two or more events happening in sequence. If events are dependent (the outcome of one affects the other), we calculate their combined probability by multiplying the probability of the first event by the conditional probability of the second event:
\( P(A \text{ and } B) = P(A) \times P(B|A) \).
In our tulip problem, to find the probability of two specific events, like selecting a red bulb first and then a yellow bulb second, we use: \( P(\text{Red } \text{first}) \times P(\text{Yellow } \text{second}| \text{Red } \text{first}) = (\frac{12}{30})(\frac{10}{29}) = \frac{4}{29} \).
This rule helps in understanding the likelihood of paired or sequential events where each event affects the following one.
dependent events
Events are considered dependent if the occurrence of one event affects the probability of the other event. In the given problem of selecting tulip bulbs, every selection affects the subsequent probabilities.
For instance, after picking the first bulb, the total number of bulbs decreases which alters the probabilities for the second pick. When we calculate the probability of the second tulip being red after already picking a yellow bulb, the scenario changes compared to the initial situation.
The formulas we use for these calculations assume this dependency. Taking another look at our step-by-step solution:
- Probability of first red bulb: \( \frac{12}{30} \).
- Probability of second red bulb given the first one was red: \( \frac{11}{29} \).
All these considerations ensure we properly account for changes in conditions as events unfold sequentially.

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Most popular questions from this chapter

A box containing twelve 40-watt light bulbs and eighteen 60 -watt light bulbs is stored in your basement. Unfortunately, the box is stored in the dark and you need two 60 -watt bulbs. What is the probability of randomly selecting two 60 -watt bulbs from the box?

List all the combinations of five objects \(a, b, c, d,\) and \(e\) taken two at a time. What is \(_5 C_{2} ?\)

Determine whether the following probabilities are computed using classical methods, empirical methods, or subjective methods. (a) The probability of having eight girls in an eight-child family is \(0.390625 \%\) (b) On the basis of a study of families with eight children, the probability of a family having eight girls is \(0.54 \%\) (c) According to a sports analyst, the probability that the Chicago Bears will win their next game is about \(30 \%\). (d) On the basis of clinical trials, the probability of efficacy of a new drug is \(75 \%\)

Use a graphing calculator or statistical software to simulate rolling a six- sided die 100 times, using an integer distribution with numbers one through six. (a) Use the results of the simulation to compute the probability of rolling a one. (b) Repeat the simulation. Compute the probability of rolling a one. (c) Simulate rolling a six-sided die 500 times. Compute the probability of rolling a one. (d) Which simulation resulted in the closest estimate to the probability that would be obtained using the classical method?

According to the U.S. Census Bureau, the probability a randomly selected individual in the United States earns more than \(\$ 75,000\) per year is \(18.4 \% .\) The probability a randomly selected individual in the United States earns more than \(\$ 75,000\) per year, given that the individual has earned a bachelor's degree, is \(35.0 \%\). Are the events "earn more than \(\$ 75,000\) per year" and "earned a bachelor's degree" independent?

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