/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 If \(P(E)=0.60, P(E \text { or }... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If \(P(E)=0.60, P(E \text { or } F)=0.85,\) and \(P(E \text { and } F)=0.05\) find \(P(F)\)

Short Answer

Expert verified
P(F) = 0.30

Step by step solution

01

Understand the Given Probabilities

Identify the probabilities given in the problem: \(P(E) = 0.60\), \(P(E \text{ or } F) = 0.85\), and \(P(E \text{ and } F) = 0.05\).
02

Use the Formula for Union of Two Events

Use the formula for the probability of the union of two events: \[ P(E \text{ or } F) = P(E) + P(F) - P(E \text{ and } F) \].
03

Substitute the Given Probabilities

Substitute the given probabilities into the formula: \[ 0.85 = 0.60 + P(F) - 0.05 \].
04

Simplify the Equation

Simplify the equation to solve for \(P(F)\): \[ 0.85 = 0.55 + P(F) \].
05

Solve for \(P(F)\)

Isolate \(P(F)\) by subtracting 0.55 from both sides of the equation: \[ P(F) = 0.85 - 0.55 \].
06

Calculate the Result

Perform the subtraction to find \(P(F)\): \[ P(F) = 0.30 \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Union of Events
In probability theory, the union of two events represents the scenario where at least one of the events occurs. This can be written as \(P(E \text{ or } F)\). To calculate the union's probability, we use the formula: \(P(E \text{ or } F) = P(E) + P(F) - P(E \text{ and } F)\). This formula ensures that we don't double-count the overlap between the two events. In our exercise, substituting the given values in the union formula helped us find the unknown probability of event F.
Conditional Probability
Conditional probability measures the probability of an event occurring, given that another event has already occurred. It is denoted as \(P(A \mid B)\), which is read as 'the probability of A given B.' However, our exercise doesn't explicitly involve conditional probability, but it's a crucial concept to understand deeper probability calculations. It often uses the formula: \[P(A \mid B) = \frac{P(A \text{ and } B)}{P(B)}\]. This formula is key for many advanced probability questions.
Event Intersection
The intersection of two events occurs when both events happen simultaneously. It is denoted as \(P(E \text{ and } F)\). This concept is essential for calculating the overlap between events, ensuring that probabilities are correctly combined. In our exercise, \(P(E \text{ and } F) = 0.05\). This value played a critical role in our calculation of \(P(F)\) by being subtracted from the sum of \(P(E) \text{ and } P(F)\) to prevent double counting in the union formula.
Probability Formulae
Probability formulae are the backbone of solving probability problems. They provide a structured way to calculate different scenarios. The key formula used in the exercise is: \[P(E \text{ or } F) = P(E) + P(F) - P(E \text{ and } F)\]. By substituting the given values, we simplify it step-by-step to isolate and determine the unknown probability. Knowing these formulae and how they interconnect can simplify complex probability calculations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Roll a single die 50 times, recording the result of each roll of the die. Use the results to approximate the probability of rolling a three. (b) Roll a single die 100 times, recording the result of each roll of the die. Use the results to approximate the probability of rolling a three. (c) Compare the results of (a) and (b) to the classical probability of rolling a three.

A box containing twelve 40-watt light bulbs and eighteen 60 -watt light bulbs is stored in your basement. Unfortunately, the box is stored in the dark and you need two 60 -watt bulbs. What is the probability of randomly selecting two 60 -watt bulbs from the box?

Suppose a local area network requires eight characters for a password. The first character must be a letter, but the remaining seven characters can be either a letter or a digit (0 through 9). Lower- and uppercase letters are considered the same. How many passwords are possible for the local area network?

List all the combinations of five objects \(a, b, c, d,\) and \(e\) taken two at a time. What is \(_5 C_{2} ?\)

According to the U.S. Bureau of Labor Statistics, there is a \(5.84 \%\) probability that a randomly selected employed individual has more than one job (a multiple-job holder). Also, there is a \(52.6 \%\) probability that a randomly selected employed individual is male, given that he has more than one job. What is the probability that a randomly selected employed individual is a multiple-job holder and male? Would it be unusual to randomly select an employed individual who is a multiple-job holder and male?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.