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91Ó°ÊÓ

Find the probability of the indicated event if \(P(E)=0.25\) and \(P(F)=0.45\) Find \(P\left(F^{c}\right)\)

Short Answer

Expert verified
The probability of the complement of event F is 0.55.

Step by step solution

01

- Understand the Complement Rule

The complement rule states that the probability of the complement of an event is 1 minus the probability of the event itself. This can be written as: \[ P(F^c) = 1 - P(F) \]
02

- Substitute the Given Probability

Substitute the given probability of event F into the complement formula. The given probability is \( P(F) = 0.45 \). Substitute this value into the equation: \[ P(F^c) = 1 - 0.45 \]
03

- Calculate the Complement

Perform the subtraction to find the complement probability: \[ P(F^c) = 0.55 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complement Rule
In probability, the complement of an event gives us the likelihood that the event does not happen. For any event F, the complement event (denoted as \(F^c\)) represents all outcomes that are not in F. The formula to calculate the probability of the complement event is quite straightforward. It states that the probability of the complement of an event is equal to 1 minus the probability of the event itself. Mathematically, this is represented as: \[ P(F^c) = 1 - P(F) \]
If you know the probability of an event occurring, you can quickly find out the probability of it not occurring by using this rule. It’s a handy tool because often it’s easier to calculate the probability of the complement. For example, imagine rolling a die. If the probability of rolling a six is \( \frac{1}{6} \), the probability of not rolling a six is \( 1 - \frac{1}{6} = \frac{5}{6} \). This demonstrates the complement rule in action.
Probability Calculation
Probability helps us measure how likely an event is to occur. It ranges from 0 to 1, where 0 means the event will not happen and 1 means it certainly will. Here’s how you can calculate probabilities:
  • Identify all possible outcomes.
  • Determine the number of favorable outcomes.
  • Divide the number of favorable outcomes by the total number of possible outcomes.
For example, if there are 4 red balls and 6 blue balls in a bag, the probability of picking a red ball is \( \frac{4}{10} = 0.4 \).
When calculating the probability of the complement, like in the given exercise:
1. We start with the probability of the event F happening, which is given as \( P(F) = 0.45 \).
2. Then, we use the complement rule: \[ P(F^c) = 1 - P(F) \]
By substituting \( P(F) \) with 0.45, we get: \[ P(F^c) = 1 - 0.45 = 0.55 \]
So, the probability that event F does not happen (the complement) is 0.55. This means there is a 55% chance that event F will not occur.
Event
An event in probability is any outcome or a set of outcomes from a random process. Events can be simple, like flipping a coin and getting heads, or complex, like drawing a red card from a shuffled deck of cards.
Events can be:
  • Independent: Occurrence of one event does not affect the other (e.g., two successive coin tosses).
  • Dependent: Occurrence of one event affects the other (e.g., drawing two cards in succession without replacement).
In the given exercise, we focus on the event F and its complement.
If event F represents something specific happening (like a rain forecast of 45% probability), \( F^c \) represents the opposite (not raining) with a probability of 55%, using our earlier calculation.
Understanding the nature of the event helps us apply probability rules accurately and effectively interpret our results.

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Most popular questions from this chapter

In Problem \(35,\) we learned that for some diseases, such as sickle-cell anemia, an individual will get the disease only if he receives both recessive alleles. This is not always the case. For example, Huntington's disease only requires one dominant gene for an individual to contract the disease. Suppose a husband and wife, who both have a dominant Huntington's disease allele \((S)\) and a normal recessive allele \((s),\) decide to have a child. (a) List the possible genotypes of their offspring. (b) What is the probability that the offspring will not have Huntington's disease? In other words, what is the probability the offspring will have genotype \(s s ?\) Interpret this probability. (c) What is the probability that the offspring will have Huntington's disease?

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