/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 In Marissa's calculus course, at... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Marissa's calculus course, attendance counts for \(5 \%\) of the grade, quizzes count for \(10 \%\) of the grade, exams count for \(60 \%\) of the grade, and the final exam counts for \(25 \%\) of the grade. Marissa had a \(100 \%\) average for attendance, \(93 \%\) for quizzes, \(86 \%\) for exams, and \(85 \%\) on the final. Determine Marissa's course average.

Short Answer

Expert verified
87.15

Step by step solution

01

Identify the weight of each component

Attendance counts for 5% of the grade, quizzes for 10%, exams for 60%, and the final exam for 25%.
02

Determine the grades for each component

Marissa's grades are: Attendance = 100%, Quizzes = 93%, Exams = 86%, Final Exam = 85%.
03

Convert percentages to decimal form

Convert each component weight into decimal form: 5% = 0.05, 10% = 0.10, 60% = 0.60, and 25% = 0.25.
04

Calculate the weighted score for each component

Multiply each grade by its respective weight: Attendance: 100% * 0.05 = 5, Quizzes: 93% * 0.10 = 9.3, Exams: 86% * 0.60 = 51.6, Final Exam: 85% * 0.25 = 21.25.
05

Sum the weighted scores

Add up all the weighted scores to find Marissa's course average: 5 + 9.3 + 51.6 + 21.25 = 87.15.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

percentage weights
When calculating a weighted average, it's important to understand the concept of percentage weights. These weights represent the relative importance of each component in the final result. For example, in Marissa's calculus course, attendance counts for 5% of her grade, meaning it's less critical compared to exams, which count for 60%. By assigning different weights, you can prioritize certain components over others, ensuring a more representative final grade.
To clearly establish the weights, let's say that:
  • Attendance = 5%
  • Quizzes = 10%
  • Exams = 60%
  • Final Exam = 25%
These weights should add up to 100% to cover the entire course's assessment criteria.
converting percentages to decimals
To properly use percentage weights in calculations, you need to convert those percentages into decimals. This step is easy but crucial for correctly computing weighted scores.
Converting a percentage to a decimal is straightforward: simply divide the percentage by 100. Here are the calculations for Marissa’s course components:
  • 5% = 5 / 100 = 0.05
  • 10% = 10 / 100 = 0.10
  • 60% = 60 / 100 = 0.60
  • 25% = 25 / 100 = 0.25
Now you have the decimal forms of the weights, ensuring you can multiply them accurately with the corresponding grades.
weighted scores
Once you have the grades and their respective weights in decimal form, it's time to calculate the weighted scores. This involves multiplying each grade by its corresponding weight. Here’s how it's done for Marissa's grades:
  • Attendance: 100% * 0.05 = 5
  • Quizzes: 93% * 0.10 = 9.3
  • Exams: 86% * 0.60 = 51.6
  • Final Exam: 85% * 0.25 = 21.25
These calculations give you the weighted contribution of each component to the final grade. By scaling the grades according to their importance, you get a more accurate reflection of overall performance.
final grade calculation
The final step in calculating the course average is to sum up all the weighted scores. This gives you the final grade, taking into account the various weights and scores:
  • Attendance = 5
  • Quizzes = 9.3
  • Exams = 51.6
  • Final Exam = 21.25
Adding these together:
5 + 9.3 + 51.6 + 21.25 = 87.15
So, Marissa’s course average is 87.15%. This integrated approach of converting percentages, computing weighted scores, and then summing them up helps in accurately determining the final grade.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain the advantage of using \(z\) -scores to compare observations from two different data sets.

Explain the circumstances under which the median and interquartile range would be better measures of central tendency and dispersion than the mean and standard deviation.

For each of the following situations, determine which measure of central tendency is most appropriate and justify your reasoning. (a) Average price of a home sold in Pittsburgh, Pennsylvania, in 2002 (b) Most popular major for students enrolled in a statistics course (c) Average test score when the scores are distributed symmetrically (d) Average test score when the scores are skewed right (e) Average income of a player in the National Football League (f) Most requested song at a radio station

Use the five test scores of 65,70 \(71,75,\) and 95 to answer the following questions: (a) Find the sample mean. (b) Find the median. (c) Which measure of central tendency best describes the typical test score? (d) Suppose the professor decides to curve the exam by adding 4 points to each test score. Compute the sample mean based on the adjusted scores. (e) Compare the unadjusted test score mean with the curved test score mean. What effect did adding 4 to each score have on the mean?

Concrete Mix A certain type of concrete mix is designed to withstand 3000 pounds per square inch (psi) of pressure. The strength of concrete is measured by pouring the mix into casting cylinders 6 inches in diameter and 12 inches tall. The cylinder is allowed to "set up" for 28 days.The cylinders are then stacked on one another until the cylinders are crushed. The following data represent the strength of nine randomly selected casts (in psi). 3960,4090,3200,3100,2940,3830,4090,4040,3780 Compute the mean, median, and mode strength of the concrete (in psi).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.