/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 An individual with apnea stops b... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An individual with apnea stops breathing while sleeping. In a randomized, double-blind study to evaluate the efficacy of caffeine citrate for treatment of apnea, infants with six or more episodes of apnea were administered \(10 \mathrm{mg} / \mathrm{kg}\) of caffeine citrate intravenously, followed by \(2.5 \mathrm{mg} / \mathrm{kg} /\) day for up to 10 days or a placebo. (Caffeine Citrate for the Treatment of Apnea in Prematurity: A Double-blind, Placebo Controlled Study, Pharmacotherapy, June \(2000,20(6): 644-652 .\) With successful treatment defined as a \(50 \%\) or more reduction in apnea episodes, it was determined that caffeine citrate was significantly more effective than the placebo in reducing apnea episodes by at least \(50 \%\) in 6 days with the \(P\) -value less than \(0.05 .\) State any conclusions, using this \(P\) -value.

Short Answer

Expert verified
Caffeine citrate is significantly more effective than placebo in reducing apnea episodes.

Step by step solution

01

Understand the Study Setup and Data

The study involves infants with apnea, who were given either caffeine citrate or a placebo. The effectiveness of the treatment is measured by a 50% or more reduction in apnea episodes, with a significant result reported if the P-value is less than 0.05.
02

Interpreting the P-value

A P-value less than 0.05 suggests that the result is statistically significant. This means that there is strong evidence against the null hypothesis, which assumes that there is no difference between the caffeine citrate and placebo.
03

Conclusion Based on P-value

Given that the P-value is less than 0.05, the study concludes that caffeine citrate is significantly more effective than the placebo in reducing apnea episodes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

P-value
The P-value is a crucial statistical metric used to determine the significance of study results. In this study, researchers used a P-value to assess whether caffeine citrate significantly reduces apnea episodes compared to a placebo.
A P-value less than 0.05 suggests that the observed effect is statistically significant. This means there's less than a 5% chance that the results are due to random variation alone.
To interpret:
  • P-value < 0.05: Strong evidence against the null hypothesis (no effect).
  • P-value ≥ 0.05: Not enough evidence to dismiss the null hypothesis.
Here, a P-value less than 0.05 led researchers to conclude that caffeine citrate indeed had a significant effect.
Randomized Double-Blind Study
A randomized double-blind study is a gold standard in clinical trials. Randomization ensures that participants are assigned to treatment or control groups by chance, reducing selection bias.
Double-blind means neither the participants nor the researchers know who receives the treatment and who gets the placebo. This minimizes bias due to the placebo effect or researcher expectations.
In the apnea study, infants were randomly assigned to receive either caffeine citrate or a placebo, and neither the infants' caregivers nor the researchers knew who received which. This setup strengthens the validity of the study findings, ensuring any observed effects are likely due to the treatment and not external factors.
Treatment Efficacy
Treatment efficacy refers to the ability of a treatment to produce a desired result under ideal conditions. In this study, efficacy is measured by a 50% or more reduction in apnea episodes.
To determine efficacy, researchers compare the outcomes in the treatment group with those in the placebo group. If the treatment group shows a significantly higher reduction in apnea episodes, the treatment is considered effective.
In simple terms:
  • More than 50% reduction in apnea episodes in the caffeine group compared to placebo.
  • P-value less than 0.05 confirms these results statistically.
The study found that caffeine citrate significantly reduced apnea episodes, demonstrating its efficacy.
Placebo-Controlled Study
A placebo-controlled study involves a group receiving the treatment and another group receiving an inactive substance (placebo). This helps isolate the treatment's effect from psychological factors.
In this trial, the placebo group received an intravenous solution that looked like the caffeine citrate but had no active ingredients. This approach ensures any differences in outcomes can be attributed to caffeine citrate.
Why use a placebo?
  • Ensures observed effects are due to the treatment, not participants' beliefs.
  • Provides a baseline to measure the treatment's true effect.
With the study design including both treatment and placebo, researchers can confidently claim caffeine citrate's effectiveness in reducing apnea episodes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether the sampling is dependent or independent. A researcher wishes to determine the effects of alcohol on people's reaction times to a stimulus. She randomly divides 100 people aged 21 or older into two groups. Group 1 is asked to drink 3 ounces of alcohol, while group 2 drinks a placebo. Both drinks taste the same, so the individuals in the study do not know which group they belong to. Thirty minutes after consuming the drink, the subjects in each group perform a series of tests meant to measure reaction time.

On March \(19-21,1999,\) the Gallup Organization surveyed 535 adults aged 18 years old or older and asked, "Do you think there is life of some form on other planets in the universe or not?" Of the 535 individuals surveyed, 326 responded yes. When the same question was asked on September \(3-5,1996,385\) of the 535 individuals surveyed responded yes. (a) Can we conclude that the proportion of adults who believe that there is life on other planets has decreased since September, \(1996,\) at the \(\alpha=0.10\) level of significance? (b) Construct a \(90 \%\) confidence interval for the difference between the two population proportions, \(p_{1996}-p_{1999}\)

On November \(3-5,2005,\) the Gallup Organization surveyed 1028 adults and found that 226 of them had smoked at least one cigarette in the past week. In \(1990,\) Gallup also asked 1028 adults the same question and determined that 278 adults had smoked at least one cigarette in the past week. Can we say the proportion of American adults who smoked at least one cigarette in the past week has decreased since \(1990 ?\) Why?

Determine whether the sampling is dependent or independent. A study was conducted by researchers designed "to determine the genetic and nongenetic factors to structural brain abnormalities on schizophrenia."The researchers examined the brains of 29 patients diagnosed with schizophrenia and compared them with 29 healthy patients. The whole-brain volumes of the two groups were compared. (Source: William F. C. Baare et al., Volumes of Brain Structures in Twins Discordant for Schizophrenia, Archives of General Psychiatry 58: (2000) 33-40.)

Kids and Leisure Young children require a lot of time. This time commitment cuts into a parent's leisure time. A sociologist wanted to estimate the difference in the amount of daily leisure time (in hours) of adults who do not have children under the age of 18 years and the amount of daily leisure time (in hours) of adults who have children under the age of 18 years. A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.62 hours with a standard deviation of 2.43 hours. A random sample of 40 adults with children under the age of 18 years results in a mean daily leisure time of 4.10 hours with a standard deviation of 1.82 hours. Construct and interpret a \(90 \%\) confidence interval for the mean difference in leisure time between adults with no children and adults with children. (Source: American Time Use Survey)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.