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Nexium Nexium is a drug that can be used to reduce the acid produced by the body and heal damage to the esophagus due to acid reflux. Suppose the manufacturer of Nexium claims that more than \(94 \%\) of patients taking Nexium are healed within 8 weeks. In clinical trials, 213 of 224 patients suffering from acid reflux disease were healed after 8 weeks. Test the manufacturer's claim at the \(\alpha=0.01\) level of significance.

Short Answer

Expert verified
Fail to reject the null hypothesis. There is not enough evidence at \( \alpha = 0.01 \) to support the claim that more than 94% of patients are healed within 8 weeks.

Step by step solution

01

State the Hypotheses

Define the null and alternative hypotheses. The null hypothesis (H_{0}) is that the proportion of patients healed is equal to 94% (0.94), and the alternative hypothesis (H_{a}) is that the proportion of patients healed is greater than 0.94.\(H_0: p = 0.94\)\(H_a: p > 0.94\)
02

Determine the Test Statistic

Calculate the sample proportion (\hat{p}) of healed patients. Use the formula \( \hat{p} = \frac{x}{n} \), where x is the number of healed patients and n is the total number of patients. For this exercise, \( \hat{p} = \frac{213}{224} \approx 0.9513 \).
03

Calculate the Standard Error

Calculate the standard error using the formula \(SE = \sqrt{\frac{p_0(1-p_0)}{n}}\), where \(p_0\) is the population proportion (null hypothesis value) and n is the sample size. Substituting the values, \( SE = \sqrt{\frac{0.94(1-0.94)}{224}} \approx 0.0161 \).
04

Compute the Z-Score

Compute the z-score using the formula \( z = \frac{\hat{p} - p_0}{SE} \). Substituting the values, \( z = \frac{0.9513 - 0.94}{0.0161} \approx 0.70 \).
05

Determine the Critical Value

Find the critical value for the significance level \( \alpha = 0.01 \) for a one-tailed test. Using standard normal (z) tables, the critical value is \( z_{critical} = 2.33 \) since it corresponds to the 99th percentile.
06

Compare Z-Score with Critical Value

Determine if the calculated z-score is greater than the critical value. Since \(0.70 < 2.33\), the z-score does not exceed the critical value.
07

Conclude the Test

Since the z-score is less than the critical value, we fail to reject the null hypothesis. There is not enough evidence at the \( \alpha = 0.01 \) level to support the claim that more than 94% of patients are healed within 8 weeks.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis (\(H_0\)) is a fundamental concept in hypothesis testing. It represents a statement of no effect or no difference and is assumed to be true until evidence suggests otherwise. In this exercise, the null hypothesis claims that the proportion of patients healed by Nexium within 8 weeks is equal to 94% (\(p = 0.94\)).
Hypothesis testing starts with the null hypothesis as the default position. If the test does not provide strong evidence against the null hypothesis, it is not rejected.
In many real-world problems, the null hypothesis helps to provide a starting point for statistical testing and enables a systematic approach to decision-making in uncertain situations.
Alternative Hypothesis
The alternative hypothesis (\(H_a\)) is what researchers aim to support through their data. It represents a new claim that opposes the null hypothesis. In this test, the alternative hypothesis suggests that the proportion of healed patients is greater than 94% (\(p > 0.94\)).
The alternative hypothesis is considered when there is strong evidence against the null hypothesis. It plays a crucial role in directional hypothesis tests, such as one-tailed tests, where the direction of the effect or difference is specified.
By setting the alternative hypothesis, researchers can determine the nature of the conclusion, such as whether a new drug or treatment is effective.
Z-Score
The z-score is a statistical measure that describes how many standard deviations a data point is from the mean. It's used in this exercise to compare the sample proportion with the null hypothesis proportion.
  • To compute the z-score, use the formula: \( z = \frac{\hat{p} - p_0}{SE} \), where \(\hat{p}\) is the sample proportion, \(p_0\) is the null hypothesis proportion, and SE is the standard error.
  • In this case, the z-score calculation is \( z = \frac{0.9513 - 0.94}{0.0161} \approx 0.70 \), indicating the sample proportion is 0.70 standard deviations away from the null hypothesis proportion.
Z-scores help standardize different data sets, allowing for comparisons across different scales and distributions. It's essential for understanding whether observed data significantly differs from the expected value.
Standard Error
The standard error (SE) measures the variability of a sample statistic (like the sample mean) from the population parameter. In this exercise, it helps to determine if the sample proportion (healing rate) of 0.9513 is significantly different from the population proportion of 0.94.
  • To compute SE, use the formula: \(SE = \sqrt{\frac{p_0(1-p_0)}{n}} \), where \(p_0\) is the null hypothesis proportion, and \(n\) is the sample size.
  • For this exercise, SE is \(\sqrt{\frac{0.94(1-0.94)}{224}} \approx 0.0161 \).
A smaller standard error indicates that the sample statistic is a more precise estimate of the population parameter. It influences the z-score, which determines the significance of the results. Therefore, understanding SE is vital for assessing the reliability of conclusions drawn from sample data.

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