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91Ó°ÊÓ

Roads A, B, and \(\mathrm{C}\) are the only escape routes from a state prison. Prison records show that, of the prisoners who tried to escape, \(30 \%\) used road \(\mathrm{A}\), \(50 \%\) used road \(\mathrm{B}\), and \(20 \%\) used road \(\mathrm{C}\). These records also show that \(80 \%\) of those who tried to escape via A, \(75 \%\) of those who try to escape via \(B\), and \(92 \%\) of those who try to escape via \(C\) were captured. What is the probability that a prisoner who succeeded in escaping used road C?

Short Answer

Expert verified
The probability that a prisoner who succeeded in escaping used road C is approximately 0.133 or 13.3%.

Step by step solution

01

Understand the Problem

Let's denote A, B, and C as the events of taking road A, B, and C. P(A), P(B), and P(C) are the probabilities that an escaping prisoner chooses each road respectively. Let's denote E as the event of an escaping prisoner not being captured. P(E|A), P(E|B), and P(E|C) are the probabilities that an escaping prisoner who chooses road A, B, and C respectively is not captured.
02

Apply Bayes' Theorem

We want to compute P(C|E), which is the probability that a prisoner who successfully escaped used road C. Bayes' theorem gives us that P(C|E) = [P(E|C) * P(C)] / P(E). Now, P(E) = P(E and A) + P(E and B) + P(E and C) = P(E|A) * P(A) + P(E|B) * P(B) + P(E|C) * P(C).
03

Compute Specific Probabilities

From the problem we know P(A) = 0.3, P(B) = 0.5, P(C) = 0.2, P(E|A) = 0.2 (since 80% of those who used road A were caught, only 20% escaped), P(E|B) = 0.25 (75% caught implies 25% escaped), and P(E|C) = 0.08 (92% caught implies 8% escaped). We substitute these values into the equations we got in the previous step.
04

Calculate the Final Answer

Substituting all known values into the formula from Step 2, we find: P(C|E) = [0.08 * 0.2] / [0.2 * 0.3 + 0.25 * 0.5 + 0.08 * 0.2] = 0.016 / 0.12 = 0.133. So the final answer is 0.133, meaning there is roughly a 13.3% chance that a prisoner who successfully escaped used road C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability helps us understand the likelihood of an event, given that another event has occurred. This is particularly powerful when dealing with situations that involve multiple possibilities. For instance, in the context of the prison escape, we're interested in finding the probability that a prisoner escaped using road C, given that they successfully escaped.
Bayes' Theorem plays a critical role here, allowing us to reverse conditional probabilities. It helps us compute \[P(C|E) = \frac{P(E|C) \times P(C)}{P(E)}\] where
  • \(P(C|E)\) is the probability that road C was used, given an escape occurred.
  • \(P(E|C)\) is the probability of escaping via C without being caught.
  • \(P(C)\) is the probability of choosing road C.
  • \(P(E)\) is the total probability of escaping.
By using these principles, you can determine the conditional probability, enhancing your understanding of scenarios where outcomes are interdependent.
Escape Probability
Escape probability refers to the likelihood of a prisoner successfully escaping without being caught, based on their chosen route. In this exercise:
  • For road A, the escape probability is 20%, since 80% of those who tried were captured.
  • For road B, it is 25%, due to 75% being apprehended.
  • For road C, only 8% escaped, with 92% detained.
These escape probabilities play a pivotal role in the final calculation using Bayes' Theorem. They provide insight into each road's effectiveness in the context of the escape and factor into determining \[P(E) = P(E|A) \times P(A) + P(E|B) \times P(B) + P(E|C) \times P(C).\] By assessing escape probabilities, you gain a clearer picture of how different choices impact the chances of success in escaping scenarios.
Event Probability
When discussing event probability, we're referring to the likelihood of a particular event occurring. This is a basic concept of probability. In this specific exercise, event probability touches on three distinct choices:
  • Choosing road A: with a probability of 30%.
  • Choosing road B: which is 50% likely.
  • Opting for road C: occurring 20% of the time.
Each of these choices is mutually exclusive and collectively exhaustive. This means each escapee's decision leads to one of these three outcomes. Hence, the sum of probabilities of events A, B, and C equals 1.
Understanding event probability lays the groundwork for tackling more complex problems, such as the conditional probability scenario in this exercise. It gives you a fundamental grasp of how different potential outcomes are quantified in probabilistic terms.

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