Chapter 5: Problem 5
In Exercises 5-10, a list of transformations is given. Find the matrix \(A\) that performs those transformations, in order, on the Cartesian plane. (a) vertical shear by a factor of 2 (b) horizontal shear by a factor of 2
Short Answer
Expert verified
The matrix is \( A = \begin{pmatrix} 5 & 2 \\ 2 & 1 \end{pmatrix} \).
Step by step solution
01
Understanding the Problem
We are asked to find a matrix that represents a sequence of transformations on the Cartesian plane. Specifically, we need to find a matrix that first performs a vertical shear by a factor of 2, followed by a horizontal shear by a factor of 2.
02
Matrix for Vertical Shear Transformation
A vertical shear transformation by a factor of 2 is represented by the matrix:\[A_1 = \begin{pmatrix} 1 & 0 \ 2 & 1 \end{pmatrix}\]This transformation keeps the x-coordinates the same and adds 2 times the x-coordinate to the y-coordinate.
03
Matrix for Horizontal Shear Transformation
A horizontal shear transformation by a factor of 2 is represented by the matrix:\[A_2 = \begin{pmatrix} 1 & 2 \ 0 & 1 \end{pmatrix}\]This transformation keeps the y-coordinates unchanged and adds 2 times the y-coordinate to the x-coordinate.
04
Multiplying the Transformation Matrices
To apply these two transformations in sequence, we multiply their matrices in the order given:\[A = A_2 \times A_1 = \begin{pmatrix} 1 & 2 \ 0 & 1 \end{pmatrix} \times \begin{pmatrix} 1 & 0 \ 2 & 1 \end{pmatrix}\]Performing the matrix multiplication, we calculate each element as follows:- First row, first column: \((1 \cdot 1) + (2 \cdot 2) = 1 + 4 = 5\)- First row, second column: \((1 \cdot 0) + (2 \cdot 1) = 0 + 2 = 2\)- Second row, first column: \((0 \cdot 1) + (1 \cdot 2) = 0 + 2 = 2\)- Second row, second column: \((0 \cdot 0) + (1 \cdot 1) = 0 + 1 = 1\)So the resulting transformation matrix is:\[A = \begin{pmatrix} 5 & 2 \ 2 & 1 \end{pmatrix}\]
05
Conclusion
The matrix that represents the sequence of transformations: first a vertical shear by a factor of 2 and then a horizontal shear by a factor of 2, is:\[A = \begin{pmatrix} 5 & 2 \ 2 & 1 \end{pmatrix}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertical Shear Transformation
In geometry, a vertical shear transformation is a linear transformation that shifts points vertically by a certain factor, while keeping the horizontal position (x-coordinate) unchanged. To understand this concept, imagine you have grid paper and you push the points vertically upwards or downwards but without altering their x-positions. This type of transformation is often used in computer graphics and animation.
When you perform a vertical shear by a factor of 2, each point on your Cartesian plane will have its y-coordinate altered as follows:
When you perform a vertical shear by a factor of 2, each point on your Cartesian plane will have its y-coordinate altered as follows:
- The x-coordinate remains the same.
- The y-coordinate becomes: \( y' = y + 2x \)
Horizontal Shear Transformation
A horizontal shear transformation is similar to a vertical shear but affects the x-coordinate instead. This transformation alters the x-coordinate of points across the Cartesian plane, shifting them horizontally and maintaining the y-coordinate constant. Visualize this as you apply a push on a horizontal axis, causing points to glide sideways.
- The y-coordinate stays unchanged.
- The x-coordinate transforms as \( x' = x + 2y \)
Matrix Multiplication in Transformations
Matrix multiplication is a critical operation when dealing with sequences of transformations. This is because multiple transformations can be condensed into a single matrix through multiplication, allowing all transformations to be applied simultaneously. In this exercise, we have a vertical shear followed by a horizontal shear.
The transformation matrices are represented as \(A_1\) for the vertical shear and \(A_2\) for the horizontal shear. To find a single matrix \(A\) that performs both transformations in order, you multiply these two matrices:\[A = A_2 \times A_1 = \begin{pmatrix} 1 & 2 \ 0 & 1 \end{pmatrix} \times \begin{pmatrix} 1 & 0 \ 2 & 1 \end{pmatrix}\]The resulting matrix \(A\) is calculated by multiplying corresponding rows and columns. Each element of the new matrix is derived by summing the products of corresponding elements:
The transformation matrices are represented as \(A_1\) for the vertical shear and \(A_2\) for the horizontal shear. To find a single matrix \(A\) that performs both transformations in order, you multiply these two matrices:\[A = A_2 \times A_1 = \begin{pmatrix} 1 & 2 \ 0 & 1 \end{pmatrix} \times \begin{pmatrix} 1 & 0 \ 2 & 1 \end{pmatrix}\]The resulting matrix \(A\) is calculated by multiplying corresponding rows and columns. Each element of the new matrix is derived by summing the products of corresponding elements:
- The element in the first row, first column: \( (1 \cdot 1) + (2 \cdot 2) = 5 \)
- In the first row, second column: \( (1 \cdot 0) + (2 \cdot 1) = 2 \)
- For the second row, first column: \( (0 \cdot 1) + (1 \cdot 2) = 2 \)
- Finally, the second row, second column: \( (0 \cdot 0) + (1 \cdot 1) = 1 \)