Chapter 6: Problem 34
Expand \(14^{4}\). Do not find the actual value.
Short Answer
Expert verified
The expansion of \(14^4\) is \(10^4 + 4 \times 10^3 \times 4 + 6 \times 10^2 \times 16 + 4 \times 10 \times 64 + 256\).
Step by step solution
01
Write in Exponential Form
The expression is already in exponential form i.e. \(14^4\).
02
Apply the Binomial Theorem
When expanding \((a+b)^n\), we use the binomial theorem. In this case, we consider \(14 = (10+4)\) so we need to expand \((10 + 4)^4\). The binomial theorem states: \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\).
03
List the Binomial Coefficients
For \((10+4)^4\), calculate the binomial coefficients \(\binom{4}{k}\) for \(k = 0, 1, 2, 3, 4\). These values are: \(\binom{4}{0} = 1\), \(\binom{4}{1} = 4\), \(\binom{4}{2} = 6\), \(\binom{4}{3} = 4\), \(\binom{4}{4} = 1\).
04
Expand Using the Binomial Coefficients
Using the coefficients, expand \((10+4)^4\) as follows:\(1 \cdot 10^4 \cdot 4^0 + 4 \cdot 10^3 \cdot 4^1 + 6 \cdot 10^2 \cdot 4^2 + 4 \cdot 10^1 \cdot 4^3 + 1 \cdot 10^0 \cdot 4^4\).
05
Simplify Each Term
Calculate each term individually:- \(10^4 \cdot 4^0 = 10^4\)- \(4 \cdot 10^3 \cdot 4 = 4 \cdot 10^3 \cdot 4^1\)- \(6 \cdot 10^2 \cdot 16 = 6 \cdot 10^2 \cdot 4^2\)- \(4 \cdot 10 \cdot 64 = 4 \cdot 10^1 \cdot 4^3\)- \(1 \cdot 256 = 1 \cdot 10^0 \cdot 4^4\).
06
Represent the Expanded Form
Write the expanded expression:\(10^4 + 4 \times 10^3 \times 4^1 + 6 \times 10^2 \times 4^2 + 4 \times 10^1 \times 4^3 + 1 \times 4^4\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Form
When we talk about exponential form, we are referring to a mathematical way to represent numbers that involve repeated multiplication of the same number. This is shown as a base number raised to a power or an exponent. In our exercise, when we have the expression \(14^4\), it means "14 multiplied by itself 4 times." Here, 14 is the base, and 4 is the exponent. Writing an expression in exponential form is crucial because it simplifies complex multiplication into a more digestible notation. It allows us to appreciate the power of exponential functions, especially when dealing with larger computations, and provides a clear understanding of how many times the base number is used in the multiplication. For example:
- \(2^3\) means \(2 \cdot 2 \cdot 2\)
- \(5^2\) means \(5 \cdot 5\)
Binomial Coefficients
Binomial coefficients are the numerical factors that show up when a binomial expression is expanded. The binomial theorem helps us understand how to expand an expression like \((a+b)^n\). In practice, when expanding expressions such as \((10 + 4)^4\), binomial coefficients play a big role. These coefficients are calculated using the formula for combinations: \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\), where \(!\) denotes factorial, the product of an integer and all the integers below it. For the expression \((10+4)^4\), we determine the following binomial coefficients:
- \(\binom{4}{0} = 1\)
- \(\binom{4}{1} = 4\)
- \(\binom{4}{2} = 6\)
- \(\binom{4}{3} = 4\)
- \(\binom{4}{4} = 1\)
Polynomial Expansion
Polynomial expansion involves breaking down a complex binomial expression into a sum or difference of simpler terms. Thanks to the binomial theorem, expanding expressions like \((a+b)^n\) becomes systematic and straightforward. In our case, expanding \((10 + 4)^4\) involves using the binomial coefficients to distribute and simplify each term.
Each term follows a specific pattern: \(\binom{n}{k} a^{n-k} b^k\), where you multiply the binomial coefficient by the appropriate powers of the two numbers. Here is how it is done:
Each term follows a specific pattern: \(\binom{n}{k} a^{n-k} b^k\), where you multiply the binomial coefficient by the appropriate powers of the two numbers. Here is how it is done:
- The first term is calculated as: \(1 \cdot 10^4 \cdot 4^0\)
- The second term is: \(4 \cdot 10^3 \cdot 4^1\)
- The third term is: \(6 \cdot 10^2 \cdot 4^2\)
- The fourth term is: \(4 \cdot 10^1 \cdot 4^3\)
- The fifth term is: \(1 \cdot 10^0 \cdot 4^4\)