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In a town of \((n+1)\) inhabitants, a person tells a rumor to a second person, who in turn, repeats it to a third person, etc. At each step, the recipient of the rumor is chosen at random from the \(n\) people available. Find the probability that the rumor will be told \(r\) times without returning to the originator.

Short Answer

Expert verified
The probability that the rumor will be told \(r\) times without returning to the originator is \(\left(\frac{n-1}{n}\right)^r\).

Step by step solution

01

Understand the scenario and the problem

There are \(n+1\) individuals in the town of which only one initiates the rumor. After the initial sharing, whenever the rumor is being shared, there are \(n\) people available to hear it, because the person who started it cannot hear it. The problem requires finding the probability that the rumor is told \(r\) times without being told back to the originator.
02

Calculate the probability in general

The probability of the rumor being told at any point without returning to the originator would simply be \(\frac{n-1}{n}\). This is because, at any instance of sharing, the rumor could go to \(n-1\) people (excluding the previous one) out of \(n\) available.
03

Calculate the probability of not returning to the originator after \(r\) times

Since each telling of the rumor is an independent event, the total probability of the rumor being told \(r\) times without returning to the originator is the product of the individual probabilities of each telling. Hence, the total probability is \(\left(\frac{n-1}{n}\right)^r\). This is because each sharing of the rumor has a \(\frac{n-1}{n}\) chance of not being told back to the originator and this instance happens \(r\) times.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

random selection
Random selection is a core concept in probability theory. It means that each member of a set has an equal chance of being chosen in a given process. In the scenario of the rumor in a town, once the rumor is initiated by the first person, the next person to receive the rumor is chosen at random from the remaining people. This means that any of the other \(n\) inhabitants can hear the rumor.

This process of random selection is repeated every time the rumor is shared. Random selection ensures that the choice of recipient for the rumor doesn't depend on any previous rumor-telling events. Instead, each choice is fresh and independent of past outcomes. It is akin to drawing a new name out of a hat each time without concern for the previous draws.

Understanding random selection is essential because it directly affects the calculation of our probabilities. Each random selection event will influence the chain of rumor sharing and ultimately the outcome of whether the rumor returns to the originator.
independent events
The concept of independent events is crucial for solving probability problems. In probability theory, events are independent if the occurrence or outcome of one event does not affect the occurrence or outcome of another. This means that the events are unrelated, and each event has its likelihood of happening, unaffected by others.

In the context of the rumor problem, each time the rumor is passed along, it represents an independent event. The next person to receive the rumor doesn't depend on the recipient of the previous instance. This is because the probability of choosing any particular person remains constant and unaffected by any past rumor-sharing events.
  • Every telling of the rumor happens independently of the others.
  • Each independent event has a probability of \(\frac{n-1}{n}\).
This independence is what allows us to calculate the overall probability as a product of individual probabilities. Because events are independent, we can multiply them together to understand the sequential process's cumulative likelihood without concern about changing conditions across each step.
probability calculation
Calculating probability involves understanding the chance or likelihood of certain outcomes in an event or series of events. In our rumor problem, we want to find the probability that the rumor is told \(r\) times without returning to the original spreader.

We start by noting that at each point of sharing, there's a probability of \(\frac{n-1}{n}\) for the rumor not returning to the originator. This calculation comes from the fact that after the initial sharing, there are \(n\) people who could hear the rumor, but only \(n-1\) of them will ensure it does not return.
Since these events are independent, as mentioned earlier, we multiply the probabilities together for each instance of rumor sharing. Thus, the probability that the rumor is passed \(r\) times without returning is given by \(\left(\frac{n-1}{n}\right)^r\).
  • Determine probability per event of not returning: \(\frac{n-1}{n}\).
  • Probability for \(r\) independent events: Multiply by \(r\) instance.
Understanding this calculation process shows how consecutive, independent actions contribute to a cumulative probability in larger contexts. By recognizing each event's independence, we build up a regimented and thorough approach to probability calculation.

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