Chapter 9: Problem 2
\(\mathbf{A}=\left[ \begin{array}{rr}{1} & {-1} \\ {1} & {3}\end{array}\right]\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 9: Problem 2
\(\mathbf{A}=\left[ \begin{array}{rr}{1} & {-1} \\ {1} & {3}\end{array}\right]\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
\(\mathbf{A}=\left[ \begin{array}{rrr}{0} & {1} & {0} \\ {0} & {0} & {1} \\\ {1} & {-1} & {1}\end{array}\right]\)
27\. Prove that the operator defined by \(L[\mathbf{x}]=\mathbf{x}^{\prime}-\mathbf{A x}\) , where \(\mathbf{A}\) is an \(n \times n\) matrix function and \(\mathbf{x}\) is an \(n \times 1\) differentiable vector function, is a linear operator.
34\. Prove that a fundamental solution set for the homoge- neous system $$\mathbf{x}^{\prime}(t)=\mathbf{A}(t) \mathbf{x}(t)$$ always exists on an interval \(I,\) provided \(\mathbf{A}(t)\) is continuous on \(I .\) [Hint: Use the existence and uniqueness theorem (Theorem 2\()\) and make judicious choices for \(\mathbf{x}_{0} . ]\)
(a) Show that the matrix \(\mathbf{A}=\left[ \begin{array}{lll}{2} & {1} & {6} \\ {0} & {2} & {5} \\\ {0} & {0} & {2}\end{array}\right]\) has the repeated eigenvalue \(r=2\) with multiplicity 3 and that all the eigenvectors of \(\mathbf{A}\) are of the form \(\mathbf{u}=s \operatorname{col}(1,0,0)\) (b) Use the result of part (a) to obtain a solution to the system \(\mathbf{x}^{\prime}=\mathbf{A} \mathbf{x}\) of the form \(\mathbf{x}_{1}(t)=e^{2 t} \mathbf{u}_{1} .\) (c) To obtain a second linearly independent solution to \(\mathbf{x}^{\prime}=\mathbf{A} \mathbf{x},\) try \(\mathbf{x}_{2}(t)=t e^{2 t} \mathbf{u}_{1}+e^{2 t} \mathbf{u}_{2} .[\)Hint\(:\) Show that \(\mathbf{u}_{1}\) and \(\mathbf{u}_{2}\) must satisfy \((\mathbf{A}-2 \mathbf{I}) \mathbf{u}_{1}=\mathbf{0}, \quad(\mathbf{A}-2 \mathbf{I}) \mathbf{u}_{2}=\mathbf{u}_{1} \cdot ]\) (d) To obtain a third linearly independent solution to \(\mathbf{x}^{\prime}=\mathbf{A} \mathbf{x},\) try \(\quad \mathbf{x}_{3}(t)=\frac{t^{2}}{2} e^{2 t} \mathbf{u}_{1}+t e^{2 t} \mathbf{u}_{2}+e^{2 t} \mathbf{u}_{3}\) [Hint: Show that \(\mathbf{u}_{1}, \mathbf{u}_{2},\) and \(\mathbf{u}_{3}\) must satisfy \((\mathbf{A}-2 \mathbf{I}) \mathbf{u}_{1}=\mathbf{0}, \quad(\mathbf{A}-2 \mathbf{I}) \mathbf{u}_{2}=\mathbf{u}_{1}\) \((\mathbf{A}-2 \mathbf{I}) \mathbf{u}_{3}=\mathbf{u}_{2} . ]\) (e) Show that \((\mathbf{A}-2 \mathbf{I})^{2} \mathbf{u}_{2}=(\mathbf{A}-2 \mathbf{I})^{3} \mathbf{u}_{3}=\mathbf{0}\)
RLCNetwork. The currents in the \(R L C\) network given by the schematic diagram in Figure 9.7 are governed by the following equations: $$ \begin{array}{l}{50 I_{1}^{\prime}(t)+80 I_{2}(t)=160} \\ {50 I_{1}^{\prime}(t)+800 q_{3}(t)=160} \\\ {I_{1}(t)=I_{2}(t)+I_{3}(t)}\end{array} $$ where \(\quad q_{3}(t)\) is the charge on the capacitor, \(I_{3}(t)=q_{3}(t),\) and initially \(q_{3}(0)=0.5\) coulombs and \(I_{3}(0)=0\) amps. Solve for the currents \(I_{1}, I_{2},\) and \(I_{3}\) . \([\) Hint: Differentiate the first two equations, use the third equation to eliminate \(I_{3},\) and form a normal system with \(x_{1}=I_{1}, x_{2}=I_{1},\) and \(x_{3}=I_{2} . ]\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.