Chapter 8: Problem 8
\(F\left(\frac{1}{2}, 1 ; \frac{3}{2} ;-x^{2}\right)=x^{-1} \arctan x\)
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Chapter 8: Problem 8
\(F\left(\frac{1}{2}, 1 ; \frac{3}{2} ;-x^{2}\right)=x^{-1} \arctan x\)
These are the key concepts you need to understand to accurately answer the question.
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Variable Resistor. In Section \(5.7,\) we showed that the charge \(q\) on the capacitor in a simple \(R L C\) circuit is governed by the equation \(L q^{\prime \prime}(t)+R q^{\prime}(t)+\frac{1}{C} q(t)=E(t),\) where \(L\) is the inductance, \(R\) the resistance, \(C\) the capacitance, and \(E\) the voltage source. Since the resistance of a resistor increases with temperature, let's assume hat the resistor is heated so that the resistance at time \(t\) is \(R(t)=1+t / 10 \Omega\) (see Figure \(8.5 ) .\) If \(L=0.1 \mathrm{H}\) \(C=2 \mathrm{F}, E(t) \equiv 0, q(0)=10 \mathrm{C},\) and \(q^{\prime}(0)=0 \mathrm{A}\) find at least the first four nonzero terms in a power series expansion about \(t=0\) for the charge on the capacitor.
Buckling Columns. In the study of the buckling of a column whose cross section varies, one encounters the equation $$\quad x^{n} y^{\prime \prime}(x)+\alpha^{2} y(x)=0, \quad x>0$$ where x is related to the height above the ground and y is the deflection away from the vertical. The positive constant a depends on the rigidity of the column, its moment of inertia at the top, and the load. The positive integer n depends on the type of column. For example, when the column is a truncated cone [see Figure 8.13(a) on page 474], we have $$n=4$$ (a) Use the substitution \(x=t^{-1}\) to reduce \((45)\) with \(n=4\) to the form \(\frac{d^{2} y}{d t^{2}}+\frac{2}{t} \frac{d y}{d t}+\alpha^{2} y=0, \quad t>0\) (b) Find at least the first six nonzero terms in the series expansion about \(t=0\) for a general solution to the equation obtained in part (a). (c) Use the result of part (b) to give an expansion about \(x=\infty\) for a general solution to \((45) .\)
$$x^{2} y^{n}+4 x y^{\prime}+2 y=0, \text { at } x=0$$
$$x^{2} y^{\prime \prime}+\left(x^{2}-x\right) y^{\prime}+y=0$$
\(4 x^{2} y^{\prime \prime}+4 x y^{\prime}+\left(4 x^{2}-1\right) y=0\)
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