Chapter 7: Problem 6
\(g(t)=\left\\{\begin{array}{ll}{0,} & {0< t <2} \\ {t+1,} & {2< t}\end{array}\right.\)
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Chapter 7: Problem 6
\(g(t)=\left\\{\begin{array}{ll}{0,} & {0< t <2} \\ {t+1,} & {2< t}\end{array}\right.\)
These are the key concepts you need to understand to accurately answer the question.
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Find an expansion for \(\ln \left[1+\left(1 / s^{2}\right)\right]\) in powers of 1\(/ s .\) Assuming the inverse Laplace transform can be com- puted term by term, show that \(\mathscr{L}^{-1}\left\\{\ln \left(1+\frac{1}{s^{2}}\right)\right\\}(t)=\frac{2}{t}(1-\cos t)\)
\(z^{\prime \prime}+3 z^{\prime}+2 z=e^{-3 t} u(t-2)\) \(z(0)=2, \quad z^{\prime}(0)=-3\)
$$\begin{array}{l}{y^{\prime \prime}+y=-\delta(t-\pi)+\delta(t-2 \pi)} \\\ {y(0)=0, \quad y^{\prime}(0)=1}\end{array}$$
\(y^{\prime \prime}+4 y^{\prime}+4 y=u(t-\pi)-u(t-2 \pi)\) \(y(0)=0, \quad y^{\prime}(0)=0\)
22\. $$y^{\prime}(t)-2 \int_{0}^{T} e^{t-v} y(v) d v=t, \quad y(0)=2$$
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