Chapter 7: Problem 17
17\. $$y(t)+\int_{0}^{t}(t-v) y(v) d v=1$$
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Chapter 7: Problem 17
17\. $$y(t)+\int_{0}^{t}(t-v) y(v) d v=1$$
These are the key concepts you need to understand to accurately answer the question.
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\(\begin{array}{ll}{z^{\prime}+w^{\prime}=z-w ;} & {z(0)=1} \\\ {z^{\prime}-w^{\prime}=z-w ;} &{w(0)=0}\end{array}\)
\(w^{\prime \prime}+w=u(t-2)-u(t-4)\) \(w(0)=1, \quad w^{\prime}(0)=0\)
21\. $$\begin{array}{l}{y^{\prime}(t)+y(t)-\int_{0} y(v) \sin (t-v) d v=-\sin t}, \\ {y(0)=1}\end{array}$$
18\. $$y(t)+\int_{a}^{t}(t-v) y(v) d v=t^{2}$$
Prove that if \(f\) is piecewise continuous on \([a, b]\) and \(g\) is continuous on \([a, b],\) then the product \(f g\) is piecewise continuous on \([a, b]\)
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