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The power generated or dissipated by a circuit element equals the voltage across the element times the current through the element. Show that the power dissipated by a resistor equals $$I^{2} R$$ the power associated with an inductor equals the derivative of $$(1 / 2) L I^{2}$$ and the power associated with a capacitor equals the derivative of $$(1 / 2) C E_{C}^{2}$$

Short Answer

Expert verified
The power dissipated by a resistor equals \(I^{2} R\), the power associated with an inductor equals the derivative of \(1 / 2 L I^{2}\), and the power associated with a capacitor equals the derivative of \(1 / 2 C (V^{2})\).

Step by step solution

01

Power dissipated by a resistor

When a resistor is involved, we know the formula for power is P = V x I. Since V=I x R for a resistor, by substituting, the power P = \( I^{2} R \).
02

Power associated with an inductor

Now, considering an inductor, where V = L(di/dt), by substituting this into the formula for power, we get: P = L(di/dt) x I. Now, since \( (d/dt)(1/2) L I^{2} = L(di/dt) x I \), we can see that the power associated with an inductor equals the derivative of \(1 / 2 L I^{2} \).
03

Power associated with a capacitor

Considering a capacitor, the voltage V across a capacitor is given by V = Q/C. Differentiating Q = CV with respect to time, we get dQ/dt = C(dV/dt). Now, considering power P = V x I, and current I = dQ/dt, we can substitute these to get P = Q/C x C(dV/dt) = (1/2)C(d/dt)(V^2). Hence, we observe that the power associated with a capacitor equals the derivative of \(1 / 2 C (V^{2})\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Dissipation
In electrical circuits, power dissipation is the process by which an electrical component, like a resistor, converts electrical energy into heat energy. This occurs when an electric current flows through the component, causing energy loss in the form of heat. Understanding power dissipation is important because excessive heat can damage components and affect circuit performance.

When calculating power dissipation, the basic formula to use is:
  • Power ( P ) = Voltage ( V ) x Current ( I )

However, different formulas can apply depending on the component in focus. For resistors, inductor, and capacitor, this basic understanding takes a unique form, making it essential to delve into each component for practical circuit analysis.
Resistor Power Calculation
For a resistor, determining the power dissipated is crucial to ensure that it operates within safe limits and doesn’t overheat. Resistors obey Ohm’s Law, where the voltage across a resistor ( V ) equals the product of the current through it ( I ) and its resistance ( R ). Therefore, the formula for power dissipation in a resistor becomes:
  • Power ( P ) = V x I
  • Since V = I x R , substitute to get P = I^2 R
This equation, I^2 R , is useful as it shows the relationship between electrical current, resistance, and power dissipation exclusively in terms of current and resistance. This method is especially helpful when only current and resistance values are known.

Understanding this equation, you can predict the power lost as heat in a resistor by knowing only its resistance and the current running through it.
Inductor Power Calculation
In inductors, power calculation differs as inductors are energy storage devices. They store energy in a magnetic field when a current flows through them. The law governing an inductor’s behavior is defined by the induced voltage:
  • V = L (d I /d t )
where L is the inductance, d I/d t is the rate of change of current. The power associated with an inductor, typically, is given as:
  • Power ( P ) = L (di/dt) x I
  • This is the derivative of the energy stored: (1/2) L I^2
This equation states that the power is equivalent to the derivative of the energy stored, showing the change in energy over time. It's essential to calculate this for understanding the dynamic performance of inductors within circuits.
Capacitor Power Calculation
Capacitors also store energy, but in the form of an electric field between their plates. The power associated with a capacitor is determined by differentiating the energy stored. For capacitors, this energy stored can be expressed as:

Q = CV , where Q is the charge. The voltage across the capacitor V is Q / C . By differentiating respect to time, dQ/dt = C(dV/dt) , we link it to current ( I ) as I = dQ/dt .

Then, substituting in the expression for power:
  • Power ( P ) = V x I = (1/2) C (d/dt)(V^2)
This indicates that the power associated with a capacitor results from the time-derivative of half the product of capacitance and the voltage squared. This connection between power and the change in energy helps in understanding capacitors’ roles in circuit dynamics and filtering applications.

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