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Show that when Euler's method is used to approximate the solution of the initial value problem $$y ^ { \prime } = 5 y , \quad y ( 0 ) = 1$$, at $$x = 1$$, then the approximation with step size h is $$( 1 + 5 h ) ^ { 1 / h }$$.

Short Answer

Expert verified
Applying Euler's method to solve the differential equation, we get the approximation of the solution at x=1 to be \((1+5h)^{1/h}\).

Step by step solution

01

Identify the differential equation and initial conditions

The given differential equation is \(y' = 5y\), and the initial values are \(y(0) = 1\) and a step size \(h\).
02

Apply Euler's method

Euler's method states that we approximate the next value of y using this formula: \(y_{n+1} = y_n + h * y'_n\), where \(y'_n\) is the derivative of y at point \(y_n\). Using the given differential equation, this becomes \(y_{n+1} = y_n + h * (5 * y_n) = y_n(1+5h)\). In this case, \(y_n = y(0) = 1\) as the initial condition, and \(y_{n+1} = y(1) = 1(1 + 5h)\).
03

Deduce the solution when x = 1

Applying Euler’s method iteratively to increment x by the step-size h until x=1, we get \(y(1/h) = 1(1+5h)^{1/h}\) as the function is applied 1/h times.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equation
A differential equation is a mathematical equation that relates a function with its derivatives. In simple terms, it describes the rate of change of a quantity. Differential equations are critical in modeling real-world phenomena where change is constant, such as population growth, heat transfer, or loan interest accumulations. For example, in the exercise provided, the differential equation is \( y' = 5y \). Here, \( y' \) represents the derivative of \( y \), indicating how \( y \) changes with respect to another variable, typically time or space. The coefficient \( 5 \) suggests that the rate of change of \( y \) is proportional to the current value of \( y \).
Understanding differential equations is crucial for solving not only theoretical mathematical problems but also for applications in physics, engineering, and beyond. Treat them as a window into the behavior of changing systems.
Initial Value Problem
An initial value problem (IVP) specifies the value of the function at a certain point, often the starting point, as part of the problem statement. In solving differential equations, knowing an initial condition is necessary to find a specific solution, since multiple functions can satisfy the general differential equation.
In the given task, the IVP is \( y'(0) = 1 \). This indicates that at the initial point, \( x = 0 \), the function's value, \( y \), starts at 1. The goal is to find the function \( y \) that fits the differential equation and meets this initial condition. The initial value serves as an anchor or starting point for approximating the function using numerical methods like Euler's Method.
Numerical Approximation
Numerical approximation involves finding a close estimate of the solution to mathematical problems that may not have an exact solution or whose exact solution is difficult to calculate. Euler’s method is one such technique for approximating solutions to differential equations.
In this context, Euler's method uses a step-by-step process to approximate the solution of an initial value problem. Starting from the initial value, it computes the next point by using the derivative to predict the next value of the function. It involves calculating the change in the function, then applying this incrementally across the domain using the starting value. This iterative technique allows us to get closer to the true solution with each step.
Step Size
Step size \( h \) is a crucial parameter in numerical methods like Euler's method, dictating how much the variable \( x \) increases at each iteration. Essentially, it controls the degree of approximation versus computational intensity. A smaller step size means more iterations, leading to a potentially more accurate result but at a cost of higher computational effort.
In the problem, the step size \( h \) is used to predict the new value of \( y \) using the formula \( y_{n+1} = y_n(1 + 5h) \). A step size too large can result in significant errors, as each approximation is farther from the previous true value of the function. Conversely, a very small \( h \) might slow down the process significantly with diminishing returns on accuracy, thus striking the right balance between \( h \) and computational feasibility is essential in practice.

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