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Your neighbor goes to the post office once a month and picks up two checks, one for \(\$ 20,000\) and one for \(\$ 4,000 .\) The larger check takes four days to clear after it is deposited; the smaller one takes six days. a. What is the total float for the month? b. What is the average daily float? c. What are the average daily receipts and weighted average delay?

Short Answer

Expert verified
a. The total float for the month is $104,000. b. The average daily float is $3,466.67. c. The average daily receipts are $800, and the weighted average delay is approximately 4.33 days.

Step by step solution

01

Calculate the total float for the month

The total float for the month is the sum of the float for each check. To find the float for each check, multiply the check amount by the number of days it takes to clear: Float for the \(20,000 check = \)20,000 × 4 = $80,000 \\ Float for the $4,000 check = \$4,000 × 6 = \$24,000 Now, add both floats to find the total float. Total float for the month = Float for the \(20,000 check + Float for the \)4,000 check = \(80,000 + \)24,000 = \$104,000
02

Calculate the average daily float

To find the average daily float, we need to divide the total float for the month by the number of days in the month (assume 30 days): Average daily float = Total float for the month / 30 = $104,000 / 30 = \$3,466.67
03

Find the average daily receipts

The average daily receipts represent the average amount of money received each day. Since our neighbor receives only two checks in a month, the total amount of money received each month is \(20,000 + \)4,000 = \$24,000. Now, divide it by the number of days in the month: Average daily receipts = Total amount received in a month / 30 = $24,000 / 30 = \$800
04

Calculate the weighted average delay

The weighted average delay represents the average delay for all money received. To calculate it, we need to divide the total float for the month by the total amount of money received: Weighted average delay = Total float for the month / Total amount received in a month \\ = $104,000 / 24,000 = 4.33 \,\text{days} (approximately) So, the answers are: a. The total float for the month is $104,000. b. The average daily float is $3,466.67. c. The average daily receipts are $800, and the weighted average delay is approximately 4.33 days.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Financial Float Calculation
In finance, the term 'float' refers to the amount of money tied up in checks or electronic transfers that have been initiated but not yet processed or settled. Understanding how to calculate financial float is critical for both businesses and individuals, as it directly impacts cash flow management.

To calculate the total float, as demonstrated in our exercise, we simply multiply the value of each check by the number of days it takes to clear. For instance, a \(20,000 check that takes four days to clear results in a float of \(20,000 \times 4 = \)80,000\), while a \(4,000 check taking six days gives us a float of \(4,000 \times 6 = \)24,000\). By summing these individual floats, we determine the total float for the month, which, in our case, is \$104,000. Understanding these calculations helps in effective budgeting and liquidity management, ensuring that individuals and businesses can cover their financial obligations as they wait for the settlement of transactions.
Average Daily Float
The concept of 'average daily float' is crucial for cash flow analysis because it provides an insight into the daily cash utilization and can impact interest earnings and costs. To calculate the average daily float, we divide the monthly total float by the number of days in the month.

In our exercise, with a total float of \$104,000 for the month, and assuming a standard 30-day month, the calculation goes as follows: \[\text{Average daily float} = \frac{\text{\$104,000}}{30} = \$3,466.67\]. This tells us that on an average day, \$3,466.67 is in limbo, neither in the hands of the issuer nor the recipient. Understanding the average daily float can assist individuals and businesses in fine-tuning their cash management strategies to maximize interest income while minimizing the impact of any cash flow gaps.
Weighted Average Delay
The weighted average delay is another important concept in finance, especially when dealing with receivables and payables. It indicates the average time taken for the money to become available for use, after accounting for various delays associated with processing payments.

In the context of our textbook exercise, to find the weighted average delay, we divided the total float by the total receipts for the month: \[\text{Weighted average delay} = \frac{\text{Total float for the month}}{\text{Total amount received in a month}} = \frac{\$104,000}{\$24,000} = 4.33 \text{ days (approximately)}\]. The resulting figure, approximately 4.33 days, reflects the average length of time money is tied up and unavailable due to the processing of transactions. By monitoring and aiming to reduce the weighted average delay, businesses can enhance their cash flow, enabling them to reinvest or pay out funds more efficiently.

Improvement Note: For more accurate financial planning, it's important to align the analysis with actual bank processing times and consider adopting electronic payment methods when possible, as they often lead to shorter delays.

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Most popular questions from this chapter

Pain Free Dentistry, Inc., disburses checks every two weeks that average \(\$ 80,000\) and take seven days to clear. How much interest can the company earn annually if it delays transfer of funds from an interest-bearing account that pays .02 percent per day for these seven days? Ignore the effects of compounding interest.

Puddle of Mudd Corporation has an agreement with Lollipop Bank whereby the bank handles \(\$ 6\) million in collections a day and requires a \(\$ 500,000\) compensating balance. Puddle of Mudd is contemplating canceling the agreement and dividing its eastern region so that two other banks will handle its business. Banks A and B will each handle \(\$ 3\) million of collections a day, and each requires a compensating balance of \(\$ 300,000\). Puddle of Mudd's financial management expects that collections will be accelerated by one day if the eastern region is divided. Should the company proceed with the new system? What will be the annual net savings? Assume that the T-bill rate is 4 percent annually.

Your firm has an average receipt size of \(\$ 60 . \mathrm{A}\) bank has approached you concerning a lockbox service that will decrease your total collection time by three days. You typically receive 12,000 checks per day. The daily interest rate is .018 percent. If the bank charges a fee of \(\$ 225\) per day, should the lockbox project be accepted? What would the net annual savings be if the service were adopted?

It takes Cookie Cutter Modular Homes, Inc. about five days to receive and deposit checks from customers. Cookie Cutter's management is considering a lockbox system to reduce the firm's collection times. It is expected that the lockbox system will reduce receipt and deposit times to three days total. Average daily collections are \(\$ 140,000,\) and the required rate of return is 10 percent per year. a. What is the reduction in outstanding cash balances as a result of implementing the lockbox system? b. What is the dollar return that could be earned on these savings? c. What is the maximum monthly charge Cookie Cutter should pay for this lockbox system?

Bumper Crop, Inc., a large fertilizer distributor based in California, is planning to use a lockbox system to speed up collections from its customers located on the East Coast. A Philadelphia-area bank will provide this service for an annual fee of \(\$ 30,000\) plus 10 cents per transaction. The estimated reduction in collection and processing time is one day. If the average customer payment in this region is \(\$ 6,000\), how many customers each day, on average, are needed to make the system profitable for Bumper Crop? Treasury bills are currently yielding 5 percent per year.

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