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A study was conducted of genetic and environmental influences on cholesterol levels. The data set used for the study were obtained from a twin registry in Sweden [10]. Specifically, four populations of adult twins were studied: (1) monozygotic (MZ) twins reared apart, (2) MZ twins reared together, (3) dizygotic (DZ) twins reared apart, and (4) DZ twins reared together. One issue is whether it is necessary to correct for gender before performing more complex genetic analyses. The data in Table 8.17 were presented for total cholesterol levels for \(\mathrm{MZ}\) twins reared apart, by gender. If we assume (a) serum cholesterol is normally distributed, (b) the cholesterol levels within each sample consist of independent observations, and (c) the standard deviations for men and women are the same, then what is the name of the statistical procedure that can be used to compare the two groups?

Short Answer

Expert verified
Independent Two-Sample T-Test

Step by step solution

01

Identify the Type of Data and Test

The data consists of cholesterol levels for MZ twins reared apart, divided into two groups: men and women. We need to compare these two groups to see if there is a significant difference in cholesterol levels based on gender.
02

Check the Assumptions

Ensure that the necessary assumptions for certain statistical tests are met: (a) Cholesterol levels are normally distributed, (b) The observations in both groups are independent, and (c) The standard deviations for men and women are equal.
03

Choose the Appropriate Statistical Test

Given the assumptions are satisfied and the need to compare means of two independent groups, we can use the Independent Two-Sample T-Test. This test is appropriate when comparing the means of two independent samples with normally distributed data and equal variances.
04

Name the Statistical Procedure

The statistical procedure that can be used, given the assumptions, to compare the cholesterol levels of the two groups (men and women) is called the Independent Two-Sample T-Test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Twin Studies
Twin studies are a fascinating approach used in biostatistics to explore the influence of genetics and the environment on various traits and behaviors. Twins provide a unique opportunity to understand these influences, especially when comparing identical twins, known as monozygotic (MZ) twins, and fraternal twins, or dizygotic (DZ) twins. MZ twins are genetically identical because they come from the same egg, while DZ twins share, on average, about 50% of their genes, similar to any other siblings.

When researchers conduct twin studies, they often look at twins who were raised together and those reared apart. By doing so, they can better understand the role of shared environment versus genetics. For instance, in the real-world study of cholesterol levels mentioned earlier, scientists compared MZ and DZ twins who were reared both together and apart to determine the extent to which cholesterol levels are influenced by hereditary or environmental factors.

This type of study design helps disentangle the complicated web of genetic and environmental contributions to traits, providing crucial insights for fields like psychology, medicine, and public health.
Independent Two-Sample T-Test
The independent two-sample t-test is a statistical method used to determine if there is a significant difference between the means of two independent groups. In the context of the exercise, this test helps compare cholesterol levels between male and female MZ twins who have been reared apart. It's important to use the correct statistical test to ensure that the results are valid.

To apply the independent two-sample t-test correctly, several assumptions need to be satisfied:
  • The data should be normally distributed.
  • The observations in each group should be independent of each other.
  • The variances of the two groups should be equal.
These conditions help ensure that the test results are reliable. Once validated, the test provides a p-value, which indicates whether the differences observed are statistically significant. If the p-value is below a certain threshold (often 0.05), it suggests that the difference in means is not due to random chance.
Genetic and Environmental Influences
Understanding the origins of traits and diseases often involves dissecting genetic and environmental influences, which is at the heart of biostatistics. Genes can dictate certain characteristics, while the environment we live in can modify these genetic predispositions.

In twin studies, this distinction becomes clearer. Monozygotic twins, because they have identical genetic makeups, are great subjects for analyzing how different environments impact the same genetic foundation. Dizygotic twins, on the other hand, share less genetic similarity but still provide useful insights when raised in the same or different environments.

Researchers often use statistical methods, like the independent two-sample t-test, to investigate whether observed differences in traits, such as cholesterol levels, are significantly influenced by genetics or are a result of environmental conditions. By teasing out these influences, scientists can provide better recommendations and interventions for improving health outcomes, considering both inherent genetic risks and modifiable environmental factors.

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Most popular questions from this chapter

A study compared mean electroretinogram (ERG) amplitude of patients with different genetic types of retinitis pigmentosa (RP), a genetic eye disease that often results in blindness. The results shown in Table 8.24 were obtained for In (ERG amplitude) among patients \(18-29\) years of age. $$\begin{array}{lcc} \hline \text { Genetic type } & \text { Mean } \pm \mathrm{sd} & n \\ \hline \text { Dominant } & 0.85 \pm 0.18 & 62 \\ \text { Recessive } & 0.38 \pm 0.21 & 35 \\ \text { X-linked } & -0.09 \pm 0.21 & 28 \\ \hline \end{array}$$ What is the standard error of In(ERG amplitude) among patients with dominant RP? How does it differ from the standard deviation in the table?

A possible important environmental determinant of lung function in children is the amount of cigarette smoking in the home. Suppose this question is studied by selecting two groups: Group 1 consists of 23 nonsmoking children 5-9 years of age, both of whose parents smoke, who have a mean forced expiratory volume (FEV) of 2.1 L and a standard deviation of \(0.7 \mathrm{L} ;\) group 2 consists of 20 nonsmoking children of comparable age, neither of whose parents smoke, who have a mean FEV of \(2.3 \mathrm{L}\) and a standard deviation of \(0.4 \mathrm{L}\). Assuming this is regarded as a pilot study, how many children are needed in each group (assuming equal numbers in each group) to have a \(95 \%\) chance of detecting a significant difference using a two-sided test with \(\alpha=.05\) ?

A possible important environmental determinant of lung function in children is the amount of cigarette smoking in the home. Suppose this question is studied by selecting two groups: Group 1 consists of 23 nonsmoking children 5-9 years of age, both of whose parents smoke, who have a mean forced expiratory volume (FEV) of 2.1 L and a standard deviation of \(0.7 \mathrm{L} ;\) group 2 consists of 20 nonsmoking children of comparable age, neither of whose parents smoke, who have a mean FEV of \(2.3 \mathrm{L}\) and a standard deviation of \(0.4 \mathrm{L}\). Provide a 95\% Cl for the true mean difference in FEV between \(5-\) to 9 -year- old children whose parents smoke and comparable children whose parents do not smoke.

What test can be used to determine whether the mean balance score is the same for RA and OA patients? What are some assumptions of this test?

A study was conducted to assess the association between climate conditions in infancy and adult blood pressure and anthropometric measures (e.g., height, weight) [19]. There were 3964 British women born between 1919 and 1940 who were divided into quartiles ( \(n=991\) per quartile) according to mean summer temperature \(\left(^{\circ} \mathrm{C}\right)\) in the first year of life. The data in Table 8.34 were presented. We will assume that the distribution of adult height within a quartile is normally distributed and that the sample sizes are large enough that the \(t\) distribution can be approximated by a normal distribution. 8.143 What test can be performed to compare the mean adult height between the first (Q1) and the fourth (Q4) quartiles? (Assume that the underlying variances of adult height in \(\mathrm{Q} 1\) and \(\mathrm{Q} 4\) are the same.)

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